If xy = 2, then dy/dx isa) -x2/2b) y2c)y/xd) -2/x2Correct answer is op...
Xy = 2 (on differentiating both side) [x . dy/dx + y .1 = 0] (as, xy = 2 then x = 2/y) (now putting the value of x ) [ 2/y . dy/dx = -y ] [dy/dx = -y/2/y] [dy/dx = -y^2/2] HENCE OPTION 'd' IS CORRECT
If xy = 2, then dy/dx isa) -x2/2b) y2c)y/xd) -2/x2Correct answer is op...
Solution:
Given, xy = 2
Differentiating both sides with respect to x, we get
y(dx/dx) + x(dy/dx) = 0
dy/dx = -y/x
Substitute the value of xy = 2
dy/dx = -y/x = -2/x2
Hence, option D is the correct answer.
Explanation:
The question is based on implicit differentiation.
Implicit differentiation is a method of finding the derivative of a function that is defined implicitly by an equation.
In this case, the equation is xy = 2.
To find dy/dx, we differentiate both sides of the equation with respect to x.
Using the product rule of differentiation, we get y(dx/dx) + x(dy/dx) = 0.
Simplifying this equation, we get dy/dx = -y/x.
Substituting the value of xy = 2, we get dy/dx = -y/x = -2/x2.
Therefore, the correct answer is option D.