A solid circular shaft is subjected to pure torsion. The ratio of maximum shear stress to maximum normal stress at any point would be

- a)1 : 1
- b)1 : 2
- c)2 : 1
- d)2 : 3

Correct answer is option 'A'. Can you explain this answer?

By
Mechanical Engineer
·
Sep 05, 2018 ·Mechanical Engineering

7 Answers

Mohit Sharma
answered
Dec 19, 2018

Their will be the shear stress in the frame, hence Mohr circle will be around origin with radius of max. shear stress. Now, ratio of Max. Shear stress to Max. Normal stress is 1:1.

Vipin Kumar
answered
Jul 22, 2018

Ans a is correct because pour torsion is applied so shear stress is devloped when we draw the mohar circle we find maximum shear stress is equal to maximum normal stress.

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