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A particle of charge 1.6 x 10-19 C and mass 1.8 x 10-27 kg is moving around the path of radius 2 x 104 m with velocity 2.4 x 106 m/s. The magnetic field necessary is (in Wb/m²)
- a)13.5 x 10-6
- b)135 x 10-6
- c)0.135 x 10
- d)1.35 x 10-6
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A particle of charge 1.6 x 10-19C and mass 1.8 x 10-27kg is moving aro...
Explanation:
When an electron is projected in a uniform electric field and a uniform magnetic field, both pointing in the same direction as the electron's velocity, the following happens:
1. Electric field:
The electric field exerts a force on the electron in the direction of the field. Since the electron is negatively charged, it experiences a force opposite to the direction of the electric field. Therefore, the electric field does not affect the direction of the electron's motion.
2. Magnetic field:
The magnetic field exerts a force on the electron perpendicular to both the field direction and the electron's velocity. The force is given by the Lorentz force equation:
F = q(v x B)
where F is the force, q is the charge of the electron, v is its velocity, and B is the magnetic field.
In this case, the force is directed inward, towards the center of the circular path. The magnitude of the force is given by:
|F| = qvB
where |F| is the magnitude of the force.
Since the force is perpendicular to the velocity, it causes the electron to move in a circular path around the magnetic field lines. The radius of the path is given by:
r = mv/qB
where r is the radius of the path, m is the mass of the electron, and v is its velocity.
3. Combined effect:
Since the electric field does not affect the direction of the electron's motion, the only effect is due to the magnetic field. As the electron moves in a circular path, it loses kinetic energy due to the work done by the magnetic force. Therefore, its velocity decreases in magnitude.
Hence, the correct option is D- The electron velocity will decrease in magnitude.
When an electron is projected in a uniform electric field and a uniform magnetic field, both pointing in the same direction as the electron's velocity, the following happens:
1. Electric field:
The electric field exerts a force on the electron in the direction of the field. Since the electron is negatively charged, it experiences a force opposite to the direction of the electric field. Therefore, the electric field does not affect the direction of the electron's motion.
2. Magnetic field:
The magnetic field exerts a force on the electron perpendicular to both the field direction and the electron's velocity. The force is given by the Lorentz force equation:
F = q(v x B)
where F is the force, q is the charge of the electron, v is its velocity, and B is the magnetic field.
In this case, the force is directed inward, towards the center of the circular path. The magnitude of the force is given by:
|F| = qvB
where |F| is the magnitude of the force.
Since the force is perpendicular to the velocity, it causes the electron to move in a circular path around the magnetic field lines. The radius of the path is given by:
r = mv/qB
where r is the radius of the path, m is the mass of the electron, and v is its velocity.
3. Combined effect:
Since the electric field does not affect the direction of the electron's motion, the only effect is due to the magnetic field. As the electron moves in a circular path, it loses kinetic energy due to the work done by the magnetic force. Therefore, its velocity decreases in magnitude.
Hence, the correct option is D- The electron velocity will decrease in magnitude.
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Community Answer
A particle of charge 1.6 x 10-19C and mass 1.8 x 10-27kg is moving aro...
As the electron is moving along the direction of the magnetic field, it will experience no magnetic force, but due to an electric force acting on it opposite to the direction of electric field (as it is a negatively charged particle) the velocity of the electron will decreases.
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A particle of charge 1.6 x 10-19C and mass 1.8 x 10-27kg is moving around the path of radius 2 x 104m with velocity 2.4 x 106m/s. The magnetic field necessary is (in Wb/m²)a)13.5 x 10-6b)135 x 10-6c)0.135 x 10d)1.35 x 10-6Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A particle of charge 1.6 x 10-19C and mass 1.8 x 10-27kg is moving around the path of radius 2 x 104m with velocity 2.4 x 106m/s. The magnetic field necessary is (in Wb/m²)a)13.5 x 10-6b)135 x 10-6c)0.135 x 10d)1.35 x 10-6Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of charge 1.6 x 10-19C and mass 1.8 x 10-27kg is moving around the path of radius 2 x 104m with velocity 2.4 x 106m/s. The magnetic field necessary is (in Wb/m²)a)13.5 x 10-6b)135 x 10-6c)0.135 x 10d)1.35 x 10-6Correct answer is option 'D'. Can you explain this answer?.
A particle of charge 1.6 x 10-19C and mass 1.8 x 10-27kg is moving around the path of radius 2 x 104m with velocity 2.4 x 106m/s. The magnetic field necessary is (in Wb/m²)a)13.5 x 10-6b)135 x 10-6c)0.135 x 10d)1.35 x 10-6Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A particle of charge 1.6 x 10-19C and mass 1.8 x 10-27kg is moving around the path of radius 2 x 104m with velocity 2.4 x 106m/s. The magnetic field necessary is (in Wb/m²)a)13.5 x 10-6b)135 x 10-6c)0.135 x 10d)1.35 x 10-6Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of charge 1.6 x 10-19C and mass 1.8 x 10-27kg is moving around the path of radius 2 x 104m with velocity 2.4 x 106m/s. The magnetic field necessary is (in Wb/m²)a)13.5 x 10-6b)135 x 10-6c)0.135 x 10d)1.35 x 10-6Correct answer is option 'D'. Can you explain this answer?.
Solutions for A particle of charge 1.6 x 10-19C and mass 1.8 x 10-27kg is moving around the path of radius 2 x 104m with velocity 2.4 x 106m/s. The magnetic field necessary is (in Wb/m²)a)13.5 x 10-6b)135 x 10-6c)0.135 x 10d)1.35 x 10-6Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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ample number of questions to practice A particle of charge 1.6 x 10-19C and mass 1.8 x 10-27kg is moving around the path of radius 2 x 104m with velocity 2.4 x 106m/s. The magnetic field necessary is (in Wb/m²)a)13.5 x 10-6b)135 x 10-6c)0.135 x 10d)1.35 x 10-6Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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