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When a body moves from point A to B along a semicircular path shown in figure distant ACB is equal to 5pier displacement aob is equal to 2 r explain?
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When a body moves from point A to B along a semicircular path shown in...
Explanation:

1. Distance ACB is equal to 5πr:
- The distance ACB along the semicircular path is equal to the circumference of the circle.
- The formula for the circumference of a circle is C = 2πr.
- Since it is a semicircle, the distance ACB will be half the circumference of the circle.
- Therefore, ACB = 1/2 * 2πr = πr.
- Given that ACB = 5πr, it implies that the distance traveled along the semicircular path is 5 times the radius of the circle.

2. Displacement AOB is equal to 2r:
- Displacement is the change in position of an object.
- In this case, the displacement AOB represents the straight-line distance from point A to point B.
- The shortest distance between two points is a straight line.
- Since A and B are diametrically opposite points on the circle, the displacement AOB is equal to the diameter of the circle.
- The diameter of a circle is twice the radius, so AOB = 2r.
Therefore, the distance traveled along the semicircular path (ACB) is 5 times the radius, while the displacement from point A to B (AOB) is equal to 2 times the radius. This difference in distance and displacement is due to the curved nature of the semicircular path compared to the straight-line distance between the two points.
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When a body moves from point A to B along a semicircular path shown in figure distant ACB is equal to 5pier displacement aob is equal to 2 r explain?
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