A force of 10 N acts on a ball moving on a surface. The force of frict...
Let's, first understand it. It's given a forward force of 10N is acting. Also, we know friction force always opposes direction of motion. Now, it's asking for constant velocity. This is the question. For constant velocity, acceleration must be zero. Let me prove it for beginners. a = v-u/t Constant velocity, so v = u a = v-v/t = 0/t = 0m/s^2 Now we also know F net = ma So, F net = m(0) = 0N So, we found F net = 0N Also we know a force of +10N is already acting so, a force of -10N should also act. So, friction force must be 10N. Extra Fact: This will be the only answer for constant velocity but if question says the ball should move and doesn't ask whether it is accelerate or not then answer will be less than or equal to 10N because if static friction becomes more than 10N then obviously ball would not move. Hope it helps. Also, you can search about other types of friction like static, kinetic and limiting friction. I am unable to type all the matter here.
A force of 10 N acts on a ball moving on a surface. The force of frict...
Because no frictional force acting on the ball
and ball is moving with constant velocity
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