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Mahesh and Umesh can complete a work in 10 days and 15 days respectively. Umesh starts the work and after 5 days Mahesh also joins him. In all, the work would be completed in what time?
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Mahesh and Umesh can complete a work in 10 days and 15 days respective...
Given Data:
- Mahesh can complete the work in 10 days.
- Umesh can complete the work in 15 days.

Calculation:
Let the total work be represented as 1 unit.
- Mahesh's one day work = 1/10
- Umesh's one day work = 1/15

Working together:
- In one day, Mahesh and Umesh's combined work = 1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6

Umesh's work in 5 days:
- In 5 days, Umesh completes = 5 * (1/15) = 1/3 of the work
- Remaining work = 1 - 1/3 = 2/3

Remaining work:
- Umesh and Mahesh together complete 1/6 of the work in one day.
- Time taken to complete 2/3 of the work = (2/3) / (1/6) = 4 days

Total time taken:
- Umesh started the work 5 days before Mahesh joined.
- Total time taken = 5 days (Umesh alone) + 4 days (Umesh and Mahesh) = 9 days
Therefore, the work would be completed in 9 days.
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Mahesh and Umesh can complete a work in 10 days and 15 days respectively. Umesh starts the work and after 5 days Mahesh also joins him. In all, the work would be completed in what time?
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