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A body moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 2.00 s later is -5.00 cm, what is the magnitude of its acceleration in cm/s2 ?
- a)-16.0 cm/s2
- b)-14.0 cm/s2
- c)-12.0 cm/s2
- d)-18.0 cm/s2
Correct answer is option 'A'. Can you explain this answer?
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A body moving with uniform acceleration has a velocity of 12.0 cm/s in...
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A body moving with uniform acceleration has a velocity of 12.0 cm/s in...
DV=DX/dt=-5-3=-8/2=-4 Da=-dv/dt=-4-12=-16 we are not dividing with t because we have already found the displacement change at that time
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A body moving with uniform acceleration has a velocity of 12.0 cm/s in...
Given data:
Initial velocity, u = 12.0 cm/s (in the positive x-direction)
Initial position, x1 = 3.00 cm
Final position, x2 = -5.00 cm
Time interval, t = 2.00 s
To find: Magnitude of acceleration, a
We can use the following kinematic equation to solve this problem:
x2 = x1 + ut + (1/2)at^2
Substituting the given values into the equation, we have:
-5.00 cm = 3.00 cm + (12.0 cm/s)(2.00 s) + (1/2)a(2.00 s)^2
Simplifying the equation:
-5.00 cm = 3.00 cm + 24.0 cm + a(2.00 s)^2
-5.00 cm = 27.00 cm + 4.00 as^2
-32.00 cm = 4.00 as^2
Dividing both sides of the equation by 4.00 s^2, we get:
-8.00 cm/s^2 = a
Since we are asked to find the magnitude of acceleration, we take the absolute value of the result:
|a| = |-8.00 cm/s^2| = 8.00 cm/s^2
Therefore, the magnitude of the acceleration is 8.00 cm/s^2.
Hence, the correct answer is option A, -16.0 cm/s^2.
Initial velocity, u = 12.0 cm/s (in the positive x-direction)
Initial position, x1 = 3.00 cm
Final position, x2 = -5.00 cm
Time interval, t = 2.00 s
To find: Magnitude of acceleration, a
We can use the following kinematic equation to solve this problem:
x2 = x1 + ut + (1/2)at^2
Substituting the given values into the equation, we have:
-5.00 cm = 3.00 cm + (12.0 cm/s)(2.00 s) + (1/2)a(2.00 s)^2
Simplifying the equation:
-5.00 cm = 3.00 cm + 24.0 cm + a(2.00 s)^2
-5.00 cm = 27.00 cm + 4.00 as^2
-32.00 cm = 4.00 as^2
Dividing both sides of the equation by 4.00 s^2, we get:
-8.00 cm/s^2 = a
Since we are asked to find the magnitude of acceleration, we take the absolute value of the result:
|a| = |-8.00 cm/s^2| = 8.00 cm/s^2
Therefore, the magnitude of the acceleration is 8.00 cm/s^2.
Hence, the correct answer is option A, -16.0 cm/s^2.
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A body moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 2.00 s later is -5.00 cm, what is the magnitude of its acceleration in cm/s2 ?a)-16.0cm/s2b)-14.0cm/s2c)-12.0cm/s2d)-18.0cm/s2Correct answer is option 'A'. Can you explain this answer?
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A body moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 2.00 s later is -5.00 cm, what is the magnitude of its acceleration in cm/s2 ?a)-16.0cm/s2b)-14.0cm/s2c)-12.0cm/s2d)-18.0cm/s2Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 2.00 s later is -5.00 cm, what is the magnitude of its acceleration in cm/s2 ?a)-16.0cm/s2b)-14.0cm/s2c)-12.0cm/s2d)-18.0cm/s2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 2.00 s later is -5.00 cm, what is the magnitude of its acceleration in cm/s2 ?a)-16.0cm/s2b)-14.0cm/s2c)-12.0cm/s2d)-18.0cm/s2Correct answer is option 'A'. Can you explain this answer?.
A body moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 2.00 s later is -5.00 cm, what is the magnitude of its acceleration in cm/s2 ?a)-16.0cm/s2b)-14.0cm/s2c)-12.0cm/s2d)-18.0cm/s2Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 2.00 s later is -5.00 cm, what is the magnitude of its acceleration in cm/s2 ?a)-16.0cm/s2b)-14.0cm/s2c)-12.0cm/s2d)-18.0cm/s2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body moving with uniform acceleration has a velocity of 12.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 2.00 s later is -5.00 cm, what is the magnitude of its acceleration in cm/s2 ?a)-16.0cm/s2b)-14.0cm/s2c)-12.0cm/s2d)-18.0cm/s2Correct answer is option 'A'. Can you explain this answer?.
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