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Consider the equation Na2Co3 + 2HCl=2NaCl + CO2 + H2O.How many number of HCl molecules will react to produce 0.22gm CO2 gas?
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Consider the equation Na2Co3 + 2HCl=2NaCl + CO2 + H2O.How many number ...
Solution:
Given:
- Mass of CO2 produced = 0.22g
- Balanced chemical equation: Na2Co3 + 2HCl = 2NaCl + CO2 + H2O
Calculating moles of CO2:
- Molar mass of CO2 = 44.01 g/mol
- Moles of CO2 = Mass / Molar mass = 0.22g / 44.01 g/mol = 0.005 moles
Using stoichiometry:
- From the balanced equation, 1 mole of CO2 is produced for every 2 moles of HCl reacted.
- Moles of HCl required = 0.005 moles CO2 * (2 moles HCl / 1 mole CO2) = 0.01 moles HCl
Calculating number of HCl molecules:
- Avogadro's number (NA) = 6.022 x 10^23 molecules/mol
- Number of HCl molecules = Moles of HCl * NA = 0.01 moles * 6.022 x 10^23 molecules/mol ≈ 6.022 x 10^21 molecules
Therefore, approximately 6.022 x 10^21 molecules of HCl will react to produce 0.22g of CO2 gas.
Given:
- Mass of CO2 produced = 0.22g
- Balanced chemical equation: Na2Co3 + 2HCl = 2NaCl + CO2 + H2O
Calculating moles of CO2:
- Molar mass of CO2 = 44.01 g/mol
- Moles of CO2 = Mass / Molar mass = 0.22g / 44.01 g/mol = 0.005 moles
Using stoichiometry:
- From the balanced equation, 1 mole of CO2 is produced for every 2 moles of HCl reacted.
- Moles of HCl required = 0.005 moles CO2 * (2 moles HCl / 1 mole CO2) = 0.01 moles HCl
Calculating number of HCl molecules:
- Avogadro's number (NA) = 6.022 x 10^23 molecules/mol
- Number of HCl molecules = Moles of HCl * NA = 0.01 moles * 6.022 x 10^23 molecules/mol ≈ 6.022 x 10^21 molecules
Therefore, approximately 6.022 x 10^21 molecules of HCl will react to produce 0.22g of CO2 gas.
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Consider the equation Na2Co3 + 2HCl=2NaCl + CO2 + H2O.How many number of HCl molecules will react to produce 0.22gm CO2 gas?
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Consider the equation Na2Co3 + 2HCl=2NaCl + CO2 + H2O.How many number of HCl molecules will react to produce 0.22gm CO2 gas? for Class 9 2025 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Consider the equation Na2Co3 + 2HCl=2NaCl + CO2 + H2O.How many number of HCl molecules will react to produce 0.22gm CO2 gas? covers all topics & solutions for Class 9 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the equation Na2Co3 + 2HCl=2NaCl + CO2 + H2O.How many number of HCl molecules will react to produce 0.22gm CO2 gas?.
Consider the equation Na2Co3 + 2HCl=2NaCl + CO2 + H2O.How many number of HCl molecules will react to produce 0.22gm CO2 gas? for Class 9 2025 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Consider the equation Na2Co3 + 2HCl=2NaCl + CO2 + H2O.How many number of HCl molecules will react to produce 0.22gm CO2 gas? covers all topics & solutions for Class 9 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the equation Na2Co3 + 2HCl=2NaCl + CO2 + H2O.How many number of HCl molecules will react to produce 0.22gm CO2 gas?.
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