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The diagonals of rhombus measure 16 cm and 30 cm. Find its perimeter. step by step explanation.?
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The diagonals of rhombus measure 16 cm and 30 cm. Find its perimeter. ...
Given:
Diagonals of the rhombus measure 16 cm and 30 cm.

To Find:
Perimeter of the rhombus.

Solution:

Step 1: Finding the Side Length
Let the diagonals of the rhombus be AC = 16 cm and BD = 30 cm.
The diagonals of a rhombus bisect each other at right angles.
Let the point of intersection of the diagonals be O.
In triangle AOB, using Pythagoras theorem:
AB² = AO² + BO²
AB² = (1/2 * AC)² + (1/2 * BD)²
AB² = (1/2 * 16)² + (1/2 * 30)²
AB² = 64 + 225
AB² = 289
AB = √289
AB = 17 cm

Step 2: Calculating Perimeter
The perimeter of a rhombus is 4 times the length of one of its sides.
Perimeter = 4 * AB
Perimeter = 4 * 17
Perimeter = 68 cm

Final Answer:
The perimeter of the rhombus is 68 cm.
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The diagonals of rhombus measure 16 cm and 30 cm. Find its perimeter. step by step explanation.?
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