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Following reaction can take place in both directions
For the forward reaction, rate varies with concentration of A as and for the backward reaction 
Hence, net reaction rate is
  • a)
    = K1[A] - K2[B]
  • b)
    = (K1 - K2[B])
  • c)
    = (K1[A]-K2)
  • d)
    = (k1-k2)
Correct answer is option 'B'. Can you explain this answer?
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Following reaction can take place in both directionsFor the forward re...
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Following reaction can take place in both directionsFor the forward reaction, rate varies with concentration of A as and for the backward reactionHence, net reaction rate isa)= K1[A] - K2[B]b)= (K1 - K2[B])c)= (K1[A]-K2)d)= (k1-k2)Correct answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Following reaction can take place in both directionsFor the forward reaction, rate varies with concentration of A as and for the backward reactionHence, net reaction rate isa)= K1[A] - K2[B]b)= (K1 - K2[B])c)= (K1[A]-K2)d)= (k1-k2)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Following reaction can take place in both directionsFor the forward reaction, rate varies with concentration of A as and for the backward reactionHence, net reaction rate isa)= K1[A] - K2[B]b)= (K1 - K2[B])c)= (K1[A]-K2)d)= (k1-k2)Correct answer is option 'B'. Can you explain this answer?.
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