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The function y = tan–1 x – x
  • a)
    is always decreasing
  • b)
    is always increasing
  • c)
    first increases and then decreases
  • d)
    first decreases and then increases 
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The function y = tan1 x xa)is always decreasingb)is always increasing...
Understanding the Function y = tan(1/x)
The function \( y = \tan(1/x) \) exhibits specific behavior based on its mathematical properties.

1. Domain of the Function
- The function is defined for all \( x \) except \( x = 0 \).
- As \( x \) approaches 0 from either side, \( 1/x \) approaches infinity, causing \( \tan(1/x) \) to oscillate between positive and negative infinity.

2. Behavior of the Function
- For positive \( x \), \( 1/x \) decreases as \( x \) increases.
- The \( \tan \) function is periodic and increases from \( -\infty \) to \( +\infty \) within each interval of \( \pi \).

3. Derivative Analysis
- To determine if \( y = \tan(1/x) \) is increasing or decreasing, we can look at the derivative.
- The derivative \( y' = \sec^2(1/x) \cdot (-1/x^2) \) indicates that:
- \( \sec^2(1/x) \) is always positive where defined.
- The factor \( -1/x^2 \) is negative for all \( x \neq 0 \).
- Hence, \( y' < 0="" \)="" for="" all="" \(="" x="" /> 0 \) and \( x < 0="" \),="" confirming="" that="" the="" function="" is="" decreasing="" in="" both="" />

4. Conclusion
- Since the function consistently decreases and does not have any intervals of increase, the correct answer is option 'A': the function \( y = \tan(1/x) \) is always decreasing.
This analysis highlights the monotonic behavior of the function across its domain.
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