Express the following in standard form : (2 –; √3i) (2 + √3i) + 2 – 4i...
It is in the form of (a+b)(a-b) hence 2 square +root 3i square. (i square =-1) (4-3 (-1))+2-4i =9-4i hence proved hope that helps you.
Express the following in standard form : (2 –; √3i) (2 + √3i) + 2 – 4i...
To express the expression (2 – √3i) (2 + √3i) in standard form, we need to simplify the expression.
Let's start by using the formula for multiplying two complex numbers: (a + bi)(c + di) = (ac - bd) + (ad + bc)i.
Here, a = 2, b = -√3, c = 2, and d = √3.
So, we can apply the formula to simplify the expression:
(2 – √3i) (2 + √3i) = (2 * 2 - (-√3 * √3)) + (2 * √3 + 2 * -√3)i
= (4 + 3) + (2√3 - 2√3)i
= 7 + 0i
= 7
Therefore, the expression (2 – √3i) (2 + √3i) simplifies to 7.
Now, let's express the expression (2 - 4i)(3 + 4i) in standard form.
Using the same formula for multiplying complex numbers, we have:
(2 - 4i)(3 + 4i) = (2 * 3 - (-4 * 4)) + (2 * 4 + 3 * 4)i
= (6 + 16) + (8 + 12)i
= 22 + 20i
Therefore, the expression (2 - 4i)(3 + 4i) simplifies to 22 + 20i.
In standard form, a complex number is expressed as a + bi, where a and b are real numbers.
So, the expression (2 - √3i)(2 + √3i) is already in standard form, and it simplifies to 7.
The expression (2 - 4i)(3 + 4i) is not in standard form, but it simplifies to 22 + 20i, which is in standard form.
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