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The minimum number of comparisons required to determine if an integer appears more than n/2 times in a sorted array of n integers is
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The minimum number of comparisons required to determine if an integer ...
whenever there exists an element which is present in the array : more than n/2 times, then definitely it will be present at the middle index position; in addition to that it will also be present at anyone of the neighbourhood indices namely i - 1 and i + 1 
No matter how we push that stream of More than n/2 times of elements of same value around the Sorted Array, it is bound to be present at the middle index + atleast anyone of its neighbourhood once we got the element which should have occurred more that n/2 times.we count its total occurrences in O(logn) time. 
To check whether a given number is repeated n/2 times in the array can be done in O(log n) time.
Algo
1. find the first occurrence (index i) of x(given number) in the array which can be done in O(log n) time (a variant of binary search).
2. check if A[i] == A[n/2+i]
return true
3. else return false
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