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Product of two co-prime numbers is 117. Then their L.C.M. is (SSC CGL 2013)
- a)13
- b)39
- c)117
- d)9
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Product of two co-prime numbers is 117. Then their L.C.M. is (SSC CG...
HCF of two-prime numbers = 1
∴ Product of numbers = their LCM = 117
∴ Product of numbers = their LCM = 117
Most Upvoted Answer
Product of two co-prime numbers is 117. Then their L.C.M. is (SSC CG...
Understanding Co-prime Numbers
Co-prime numbers are pairs of numbers that have no common factors other than 1. This means that their greatest common divisor (GCD) is 1.
Given Information
We know that the product of two co-prime numbers is 117. Let's denote these numbers as \( a \) and \( b \). Therefore, we can express this as:
- \( a \times b = 117 \)
Finding the LCM of Co-prime Numbers
The Least Common Multiple (LCM) of two numbers can be calculated using the formula:
- \( \text{LCM}(a, b) = \frac{a \times b}{\text{GCD}(a, b)} \)
Since \( a \) and \( b \) are co-prime, their GCD is 1. Therefore, the formula simplifies to:
- \( \text{LCM}(a, b) = \frac{a \times b}{1} = a \times b \)
Calculating the LCM
Substituting the known product into the LCM formula, we have:
- \( \text{LCM}(a, b) = a \times b = 117 \)
Conclusion
Thus, the LCM of the two co-prime numbers whose product is 117 is:
- 117
This means the correct answer is option C.
Understanding this concept is crucial for solving problems related to co-prime numbers and their LCM in competitive exams like SSC CGL.
Co-prime numbers are pairs of numbers that have no common factors other than 1. This means that their greatest common divisor (GCD) is 1.
Given Information
We know that the product of two co-prime numbers is 117. Let's denote these numbers as \( a \) and \( b \). Therefore, we can express this as:
- \( a \times b = 117 \)
Finding the LCM of Co-prime Numbers
The Least Common Multiple (LCM) of two numbers can be calculated using the formula:
- \( \text{LCM}(a, b) = \frac{a \times b}{\text{GCD}(a, b)} \)
Since \( a \) and \( b \) are co-prime, their GCD is 1. Therefore, the formula simplifies to:
- \( \text{LCM}(a, b) = \frac{a \times b}{1} = a \times b \)
Calculating the LCM
Substituting the known product into the LCM formula, we have:
- \( \text{LCM}(a, b) = a \times b = 117 \)
Conclusion
Thus, the LCM of the two co-prime numbers whose product is 117 is:
- 117
This means the correct answer is option C.
Understanding this concept is crucial for solving problems related to co-prime numbers and their LCM in competitive exams like SSC CGL.
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Product of two co-prime numbers is 117. Then their L.C.M. is (SSC CGL 2013)a)13b)39c)117d)9Correct answer is option 'C'. Can you explain this answer? for SSC CGL 2025 is part of SSC CGL preparation. The Question and answers have been prepared according to the SSC CGL exam syllabus. Information about Product of two co-prime numbers is 117. Then their L.C.M. is (SSC CGL 2013)a)13b)39c)117d)9Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC CGL 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Product of two co-prime numbers is 117. Then their L.C.M. is (SSC CGL 2013)a)13b)39c)117d)9Correct answer is option 'C'. Can you explain this answer?.
Product of two co-prime numbers is 117. Then their L.C.M. is (SSC CGL 2013)a)13b)39c)117d)9Correct answer is option 'C'. Can you explain this answer? for SSC CGL 2025 is part of SSC CGL preparation. The Question and answers have been prepared according to the SSC CGL exam syllabus. Information about Product of two co-prime numbers is 117. Then their L.C.M. is (SSC CGL 2013)a)13b)39c)117d)9Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC CGL 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Product of two co-prime numbers is 117. Then their L.C.M. is (SSC CGL 2013)a)13b)39c)117d)9Correct answer is option 'C'. Can you explain this answer?.
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