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A lift is moving down with the acceleration 3 m/s2. A ball is released 1.7 m above the the lift floor. How long will it take to hit the lift floor.
- a)0.5s
- b)1.7s
- c)7.1s
- d)0.71s
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A lift is moving down with the acceleration 3 m/s2. A ball is released...
Relative acceleration is,
a = 9.8 – 3 = 6.8 m/s2
Now, we have
S = ut + (1/2)at2
Here, u = 0 and S = 1.7 m
Therefore, t = 0.71 s
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Community Answer
A lift is moving down with the acceleration 3 m/s2. A ball is released...
To solve this problem, we can use the equation of motion:
s = ut + (1/2)at^2
Where:
s = distance traveled
u = initial velocity (in this case, 0 m/s as the ball is released)
a = acceleration of the lift (given as 3 m/s^2)
t = time taken
We are given:
s = 1.7 m
a = -3 m/s^2 (negative because it is moving down)
u = 0 m/s
We can plug in these values into the equation and solve for t:
1.7 = 0*t + (1/2)(-3)t^2
1.7 = (-3/2)t^2
t^2 = -1.7*(-2/3)
t^2 = 3.4/3
t^2 = 1.1333
t = √1.1333
t ≈ 1.064
Therefore, it will take approximately 1.064 seconds for the ball to hit the lift floor.
The closest option to this answer is option 'D' which is 0.71s.
s = ut + (1/2)at^2
Where:
s = distance traveled
u = initial velocity (in this case, 0 m/s as the ball is released)
a = acceleration of the lift (given as 3 m/s^2)
t = time taken
We are given:
s = 1.7 m
a = -3 m/s^2 (negative because it is moving down)
u = 0 m/s
We can plug in these values into the equation and solve for t:
1.7 = 0*t + (1/2)(-3)t^2
1.7 = (-3/2)t^2
t^2 = -1.7*(-2/3)
t^2 = 3.4/3
t^2 = 1.1333
t = √1.1333
t ≈ 1.064
Therefore, it will take approximately 1.064 seconds for the ball to hit the lift floor.
The closest option to this answer is option 'D' which is 0.71s.
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A lift is moving down with the acceleration 3 m/s2. A ball is released 1.7 m above the the lift floor. How long will it take to hit the lift floor.a)0.5sb)1.7sc)7.1sd)0.71sCorrect answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A lift is moving down with the acceleration 3 m/s2. A ball is released 1.7 m above the the lift floor. How long will it take to hit the lift floor.a)0.5sb)1.7sc)7.1sd)0.71sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A lift is moving down with the acceleration 3 m/s2. A ball is released 1.7 m above the the lift floor. How long will it take to hit the lift floor.a)0.5sb)1.7sc)7.1sd)0.71sCorrect answer is option 'D'. Can you explain this answer?.
A lift is moving down with the acceleration 3 m/s2. A ball is released 1.7 m above the the lift floor. How long will it take to hit the lift floor.a)0.5sb)1.7sc)7.1sd)0.71sCorrect answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A lift is moving down with the acceleration 3 m/s2. A ball is released 1.7 m above the the lift floor. How long will it take to hit the lift floor.a)0.5sb)1.7sc)7.1sd)0.71sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A lift is moving down with the acceleration 3 m/s2. A ball is released 1.7 m above the the lift floor. How long will it take to hit the lift floor.a)0.5sb)1.7sc)7.1sd)0.71sCorrect answer is option 'D'. Can you explain this answer?.
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