If x and y are consecutive positive integer multiples of 3, what is th...
Understanding the Problem
We need to find the greatest integer j such that the expression xy/j is always an integer, where x and y are consecutive positive integer multiples of 3.
Defining x and y
- Let x = 3n (first multiple of 3)
- Let y = 3(n + 1) (next consecutive multiple of 3)
Calculating xy
- The product xy can be expressed as:
xy = (3n)(3(n + 1)) = 9n(n + 1)
Factors of xy
- The expression 9n(n + 1) consists of:
- 9 (which is 3^2)
- n (a positive integer)
- (n + 1) (the next consecutive integer, hence coprime to n)
Finding j
- To ensure xy/j is always an integer, j must divide 9n(n + 1).
- The factors of 9 are 1, 3, and 9.
Analyzing Divisibility
- Since n and n + 1 are consecutive integers, at least one of them is always even.
- Therefore, the product n(n + 1) is even, ensuring xy is always divisible by 2.
Determining the Greatest j
- The product xy is divisible by 9 (from the factor 9).
- The minimum j that can provide an integer result for xy/j is the highest factor of 9 that is still guaranteed to divide the product.
Conclusion
- The greatest integer j such that xy/j is always an integer is 9. However, we need to ensure it divides 9n(n + 1) for all positive integers n, which leads us to consider the factors of 18.
Thus, the correct answer is option B (18), as it encompasses all scenarios where n(n + 1) remains even.
If x and y are consecutive positive integer multiples of 3, what is th...
Understanding the Problem
To solve the problem, we need to identify consecutive positive integer multiples of 3, denoted as x and y.
Identifying x and y
- Let x = 3n (the first multiple of 3)
- Consequently, y = 3(n + 1) (the next consecutive multiple of 3)
Thus, we can express the product xy as follows:
Calculating the Product xy
- xy = (3n) * (3(n + 1)) = 9n(n + 1)
Finding the Divisor j
We want to find the greatest integer j such that xy/j is an integer for any positive integer n. To do this, we will analyze the factors of 9n(n + 1).
- The term n(n + 1) consists of two consecutive integers, ensuring that one of them is even. Hence, n(n + 1) is always at least divisible by 2.
Determining the Greatest j
- The product xy = 9n(n + 1) contains:
- A factor of 9 (which is 3^2)
- A factor of at least 2 from n(n + 1)
Therefore, the total product can be expressed in terms of its prime factors:
- xy = 2^1 * 3^2 * k (where k is some integer based on n)
To find the greatest j that divides xy, we need the maximum constant divisor that can be divided out:
- The constant factors are 2 and 9.
Combining these factors, the highest j that divides xy for any n is:
Conclusion
- The greatest integer j is 18 (2 * 9), which means j = 18 fits all conditions required to ensure that xy/j is always an integer.
Thus, the answer is option 'B': 18.