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Three pipes A, B and C can fill a cistern in 6 hours. After working at it together for 2
hours, A and B are closed and C filled it in 7 hours. What is the time taken by C
alone to fill the cistem?
Most Upvoted Answer
Three pipes A, B and C can fill a cistern in 6 hours. After working at...
Understanding the Problem
To solve the problem, we first need to determine the rates at which pipes A, B, and C fill the cistern.
Combined Rate of A, B, and C
- The three pipes together can fill the cistern in 6 hours.
- Therefore, their combined rate is 1/6 of the cistern per hour.
Work Done in Two Hours
- When A, B, and C work together for 2 hours, they fill:
- Work done = 2 hours × (1/6) = 1/3 of the cistern.
Remaining Work for Pipe C
- After 2 hours, the remaining work to fill the cistern is:
- 1 - 1/3 = 2/3 of the cistern.
Time Taken by Pipe C
- Pipe C fills the remaining 2/3 of the cistern in 7 hours.
- Therefore, C's rate of work is:
- Rate of C = (2/3) / 7 = 2/21 of the cistern per hour.
Finding the Rates of A and B
- Let the rates for A and B be represented as 'a' and 'b' respectively.
- We know:
- a + b + (2/21) = 1/6 (combined rate).
Calculating A and B's Rate
- Rearranging gives us:
- a + b = 1/6 - 2/21.
- To solve this, we convert to a common denominator (42):
- 1/6 = 7/42, and 2/21 = 4/42.
- Therefore:
- a + b = 7/42 - 4/42 = 3/42 = 1/14.
Finding Time Taken by A Alone
- If a + b = 1/14, we need to express A's contribution.
- The time taken by A alone to fill the cistern can be calculated by:
- Time = 1/a, where a = 1/14 - b.
- By solving further, we can find the time taken by A alone.
In conclusion, once we determine the individual rates of A and B, we can calculate the time taken by C (1/(2/21)) and find the overall filling times.
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Three pipes A, B and C can fill a cistern in 6 hours. After working at it together for 2hours, A and B are closed and C filled it in 7 hours. What is the time taken by Calone to fill the cistem?
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