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The sum of a certain number of terms of an AP series –8, –6, –4,…… is 52. The number of terms is
  • a)
    12
  • b)
    13
  • c)
    11
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The sum of a certain number of terms of an AP series –8, –...
Let the number of terms is N.
Given,
First term ( a ) = -8
Common difference ( d ) = Difference of two consecutive terms
= ( -6 ) - ( -8 ) = -6 + 8 = 2.
Now,

⇒ Sum of  N terms of an A.P. = N/2 { 2 a + ( N - 1 ) d }

⇒ 52 = N/2 { 2 x ( -8 ) + ( N - 1 )2 }

⇒ 52 = N/2 { -16 + 2N - 2 }

⇒ 52 = N/2 ( -18 + 2N )

⇒ 52 x 2 = N ( -18 + 2N )

⇒ 104 = -18N + 2N^2

⇒ 104 = 2 ( -9N + N^2 )

⇒ 104/2 = -9N + N^2

⇒ 52 = -9N + N^2

⇒ 0 = N^2 - 9N - 52

⇒ 0 = N^2 - 13N + 4N - 52

⇒ 0 = N ( N - 13 ) + 4 ( N - 13 )

⇒ 0 = ( N - 13 ) ( N + 4 )

∴ N = either 13 or -4.

But the numbers of terms in an A.P. can't be negative.

Therefore, the possible value is 13.
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The sum of a certain number of terms of an AP series –8, –...
Given: AP series 8, 6, 4 and sum of certain number of terms is 52

To find: Number of terms in AP series

Approach:

Let the first term of AP be 'a' and common difference be 'd'

Sum of n terms of AP formula: Sn = n/2 [2a + (n-1)d]

Given, Sn = 52

Substituting a=8 and d=-2 in the formula: 52 = n/2 [16 - 2n + 2]

Simplifying the equation, we get 2n² - 26n + 72 = 0

Solving the quadratic equation using the formula (-b ± sqrt(b²-4ac))/2a, we get n=6, 12

As the number of terms in the series is positive, we can neglect n=6

Therefore, the number of terms in the AP series is 12

Answer: Option (B) 13
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The sum of a certain number of terms of an AP series –8, –6, –4,…… is 52. The number of terms isa)12b)13c)11d)None of theseCorrect answer is option 'B'. Can you explain this answer?
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