The area of triangle whose adjacent sides are is :

- a)√70/2 sq. units
- b)9√2 /2 sq. units
- c)3√3 /2 sq. units
- d)2√3 /2 sq. units

Correct answer is option 'A'. Can you explain this answer?

Related Test: Test: Cross Product

14 Answers

Shubham Karande
answered
Aug 29, 2018

Do the cross product. You will get the area of parallelogram and then divide it by 2, you will get the area of triangle

Shreya Singh
answered
Sep 16, 2018

Area of triangle is =1/2|ab|.

on doing ab cross product =|6i^-5j^+3k^|=âˆš36+25+9=âˆš70...

area of triangle=1/2(âˆš70).

=âˆš70/2....

on doing ab cross product =|6i^-5j^+3k^|=âˆš36+25+9=âˆš70...

area of triangle=1/2(âˆš70).

=âˆš70/2....

Shweta Bhamu
answered
yesterday

Area of triangle =1/2Ã—modulous (axb) wher 'a' and 'b' adjacents side vecto of triangle.

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