The area of triangle whose adjacent sides are is :
  • a)
    √70/2 sq. units
  • b)
    9√2 /2 sq. units
  • c)
    3√3 /2 sq. units
  • d)
    2√3 /2 sq. units
Correct answer is option 'A'. Can you explain this answer?
Related Test: Test: Cross Product

JEE Question

Suresh Kumar
May 13, 2020

Vikas Singh
Nov 17, 2020
A cross B by 2 is the answer will give the area of triangle because A cross B gives area of parallelogram and in parallelogram it is divided into 2 equal parts so divide the area of parallelogram by 2 gives the area of triangle

Area = 1/2 × | a × b | = √70/2

Navya Hegde
Apr 09, 2020
Hence option A is the correct one

Mohit Mittal
Jul 01, 2020
Area = 1/2 ( cross product of both vectors of adjacent side )

Shubham Karande
Aug 29, 2018
Do the cross product. You will get the area of parallelogram and then divide it by 2, you will get the area of triangle

Shweta Bhamu
May 28, 2020
Area of triangle =1/2×modulous (axb) wher 'a' and 'b' adjacents side vecto of triangle.

Shreya Singh
Sep 16, 2018
Area of triangle is =1/2|ab|.
on doing ab cross product =|6i^-5j^+3k^|=√36+25+9=√70...
area of triangle=1/2(√70).
=√70/2....

Sudesh Kumar
Jun 07, 2020
Cross multiply the two vectors by matrices or by other methods and then divide by 2

Gayatri Devi
Aug 19, 2020
You will easily get the answer by the standard cross product formulae :(|a×b|)/2.sqrt70/2 is the answer.

Krit Goswami
Jul 01, 2020
Correct answer is a

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