The area of triangle whose adjacent sides are is :

- a)√70/2 sq. units
- b)9√2 /2 sq. units
- c)3√3 /2 sq. units
- d)2√3 /2 sq. units

Correct answer is option 'A'. Can you explain this answer?

Related Test: Test: Cross Product

23 Answers

Shubham Karande
answered
Aug 29, 2018

Do the cross product. You will get the area of parallelogram and then divide it by 2, you will get the area of triangle

Shweta Bhamu
answered
May 28, 2020

Area of triangle =1/2Ã—modulous (axb) wher 'a' and 'b' adjacents side vecto of triangle.

Shreya Singh
answered
Sep 16, 2018

Area of triangle is =1/2|ab|.

on doing ab cross product =|6i^-5j^+3k^|=âˆš36+25+9=âˆš70...

area of triangle=1/2(âˆš70).

=âˆš70/2....

on doing ab cross product =|6i^-5j^+3k^|=âˆš36+25+9=âˆš70...

area of triangle=1/2(âˆš70).

=âˆš70/2....

Sudesh Kumar
answered
Jun 07, 2020

Cross multiply the two vectors by matrices or by other methods and then divide by 2

Gayatri Devi
answered
Aug 19, 2020

You will easily get the answer by the standard cross product formulae :(|aÃ—b|)/2.sqrt70/2 is the answer.

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