The area of triangle whose adjacent sides are is :
  • a)
    √70/2 sq. units
  • b)
    9√2 /2 sq. units
  • c)
    3√3 /2 sq. units
  • d)
    2√3 /2 sq. units
Correct answer is option 'A'. Can you explain this answer?
Related Test: Test: Cross Product

JEE Question

By Raviteja Velpula · Sep 16, 2018 ·JEE
23 Answers
Shashmith Shashmith answered Mar 24, 2020
Area = 1/2 × | a × b | = √70/2

Navya Hegde answered Apr 09, 2020
Hence option A is the correct one

Asiya Anjum answered Jun 01, 2020
Asiya anjum

Mohit Mittal answered Jul 01, 2020
Area = 1/2 ( cross product of both vectors of adjacent side )

Shubham Karande answered Aug 29, 2018
Do the cross product. You will get the area of parallelogram and then divide it by 2, you will get the area of triangle

Shweta Bhamu answered May 28, 2020
Area of triangle =1/2×modulous (axb) wher 'a' and 'b' adjacents side vecto of triangle.

Shreya Singh answered Sep 16, 2018
Area of triangle is =1/2|ab|.
on doing ab cross product =|6i^-5j^+3k^|=√36+25+9=√70...
area of triangle=1/2(√70).
=√70/2....

Sudesh Kumar answered Jun 07, 2020
Cross multiply the two vectors by matrices or by other methods and then divide by 2

Krit Goswami answered Jul 01, 2020
Correct answer is a

Gayatri Devi answered Aug 19, 2020
You will easily get the answer by the standard cross product formulae :(|a×b|)/2.sqrt70/2 is the answer.

Aman Kumar answered Jul 21, 2020
Correct option a

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