The area of triangle whose adjacent sides are is :
  • a)
    √70/2 sq. units
  • b)
    9√2 /2 sq. units
  • c)
    3√3 /2 sq. units
  • d)
    2√3 /2 sq. units
Correct answer is option 'A'. Can you explain this answer?
Related Test: Test: Cross Product

JEE Question

By Raviteja Velpula · Sep 16, 2018 ·JEE
14 Answers
Navya Hegde answered Apr 09, 2020
Hence option A is the correct one

Shashmith Shashmith answered Mar 24, 2020
Area = 1/2 × | a × b | = √70/2

Shubham Karande answered Aug 29, 2018
Do the cross product. You will get the area of parallelogram and then divide it by 2, you will get the area of triangle

Shreya Singh answered Sep 16, 2018
Area of triangle is =1/2|ab|.
on doing ab cross product =|6i^-5j^+3k^|=√36+25+9=√70...
area of triangle=1/2(√70).
=√70/2....

Shweta Bhamu answered yesterday
Area of triangle =1/2×modulous (axb) wher 'a' and 'b' adjacents side vecto of triangle.

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