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A 120 liters mixture of milk and water contains 45% water. How many liters of water should be added so that the resultant mixture will have 60% water?
- a)30 liters
- b)35 liters
- c)40 liters
- d)45 liters
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A 120 liters mixture of milk and water contains 45% water. How many li...
Initial mixture : added water = 40 : 15 = 8 : 3
Hence, Option D is correct.
Most Upvoted Answer
A 120 liters mixture of milk and water contains 45% water. How many li...
Understanding the Mixture
To solve the problem, we first need to determine how much water is currently in the mixture and how much we need to achieve the desired concentration.
Current Composition
- The total volume of the mixture is 120 liters.
- Water constitutes 45% of this mixture.
Calculating Current Water Volume
- Amount of water = 45% of 120 liters = 0.45 * 120 = 54 liters.
- Amount of milk = 120 liters - 54 liters = 66 liters.
Desired Composition
We want the resultant mixture to have 60% water.
Setting Up the Equation
Let "x" be the amount of water we need to add.
- New total volume of mixture = 120 liters + x liters.
- New amount of water = 54 liters + x liters.
We want the new amount of water to equal 60% of the new total volume:
(54 + x) / (120 + x) = 60/100
Solving the Equation
Cross-multiply:
- 100(54 + x) = 60(120 + x)
Expanding both sides:
- 5400 + 100x = 7200 + 60x
Rearranging:
- 100x - 60x = 7200 - 5400
- 40x = 1800
Now, divide by 40:
- x = 1800 / 40 = 45 liters.
Conclusion
Thus, to achieve a mixture that contains 60% water, you need to add 45 liters of water. The correct answer is option D.
To solve the problem, we first need to determine how much water is currently in the mixture and how much we need to achieve the desired concentration.
Current Composition
- The total volume of the mixture is 120 liters.
- Water constitutes 45% of this mixture.
Calculating Current Water Volume
- Amount of water = 45% of 120 liters = 0.45 * 120 = 54 liters.
- Amount of milk = 120 liters - 54 liters = 66 liters.
Desired Composition
We want the resultant mixture to have 60% water.
Setting Up the Equation
Let "x" be the amount of water we need to add.
- New total volume of mixture = 120 liters + x liters.
- New amount of water = 54 liters + x liters.
We want the new amount of water to equal 60% of the new total volume:
(54 + x) / (120 + x) = 60/100
Solving the Equation
Cross-multiply:
- 100(54 + x) = 60(120 + x)
Expanding both sides:
- 5400 + 100x = 7200 + 60x
Rearranging:
- 100x - 60x = 7200 - 5400
- 40x = 1800
Now, divide by 40:
- x = 1800 / 40 = 45 liters.
Conclusion
Thus, to achieve a mixture that contains 60% water, you need to add 45 liters of water. The correct answer is option D.
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A 120 liters mixture of milk and water contains 45% water. How many liters of water should be added so that the resultant mixture will have 60% water?a)30 litersb)35 litersc)40 litersd)45 litersCorrect answer is option 'D'. Can you explain this answer? for SSC CGL 2025 is part of SSC CGL preparation. The Question and answers have been prepared according to the SSC CGL exam syllabus. Information about A 120 liters mixture of milk and water contains 45% water. How many liters of water should be added so that the resultant mixture will have 60% water?a)30 litersb)35 litersc)40 litersd)45 litersCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for SSC CGL 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 120 liters mixture of milk and water contains 45% water. How many liters of water should be added so that the resultant mixture will have 60% water?a)30 litersb)35 litersc)40 litersd)45 litersCorrect answer is option 'D'. Can you explain this answer?.
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