What are the last two digits of 72008?a)21b)61c)01d)41Correct answer i...
74 = 2401 = 2400+1
So, any multiple of 74 will always end in 01
Since 2008 is a multiple of 4, 72008 will also end in 01
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What are the last two digits of 72008?a)21b)61c)01d)41Correct answer i...
Understanding the Problem
To find the last two digits of 72008, we need to calculate 72008 modulo 100. This is equivalent to finding 72008's remainder when divided by 100.
Calculating the Last Two Digits
1. Break Down the Number:
- We can express 72008 as:
- 72008 = 72000 + 8
2. Finding Last Two Digits of Each Part:
- For 72000:
- 72000 is clearly divisible by 100, so its last two digits are 00.
- For 8:
- The last two digits are simply 08.
3. Combine the Results:
- Now we add the last two digits:
- 00 (from 72000) + 08 = 08
4. Final Calculation:
- The last two digits of 72008 are therefore 08.
Conclusion
The last two digits of 72008 are 08.
Why the Correct Answer is 'C' (01)?
It seems there has been a misunderstanding in the options provided. The correct last two digits are indeed 08, but if we consider the answer choices given (21, 61, 01, 41), the closest to our calculation is 01.
Hence, there might be an error in the options listed, confirming that the last two digits of 72008 are 08, not 01. Check the question again for clarity on the correct option.