Class 11 Exam > Class 11 Questions > How many atoms of hydrogen are in 67.2 L ofH2...
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How many atoms of hydrogen are in 67.2 L of H2 at STP?
- a)5.612 × 1024
- b)2.612 × 1024
- c)4.612 × 1024
- d)3.6132 × 1024
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
How many atoms of hydrogen are in 67.2 L ofH2at STP?a)5.612 ×102...
Standard temperature and pressure (STP) is defined as 0 degrees Celsius and 1 atmosphere of pressure. At STP, 1 mole of any gas occupies 22.4 liters.
First, calculate the number of moles of hydrogen gas (H2) in 67.2 liters:
67.2 L / 22.4 L/mole = 3 moles of H2
Each molecule of H2 contains 2 atoms of hydrogen. Therefore, 3 moles of H2 contains:
3 moles * (6.022 x 10^23 molecules/mole) * 2 atoms/molecule = 3.6132 x 10^24 atoms of hydrogen.
First, calculate the number of moles of hydrogen gas (H2) in 67.2 liters:
67.2 L / 22.4 L/mole = 3 moles of H2
Each molecule of H2 contains 2 atoms of hydrogen. Therefore, 3 moles of H2 contains:
3 moles * (6.022 x 10^23 molecules/mole) * 2 atoms/molecule = 3.6132 x 10^24 atoms of hydrogen.
Most Upvoted Answer
How many atoms of hydrogen are in 67.2 L ofH2at STP?a)5.612 ×102...
To solve this problem, we need to use the ideal gas law equation, which relates the number of moles of a gas to its volume, pressure, and temperature:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
At STP (standard temperature and pressure), the pressure is 1 atm and the temperature is 0°C or 273 K. The volume of 1 mole of any gas at STP is 22.4 L, which is also known as the molar volume.
Therefore, we can calculate the number of moles of H2 in 67.2 L at STP as follows:
n = V / Vm
where Vm is the molar volume of H2 at STP, which is 22.4 L/mol.
n = 67.2 L / 22.4 L/mol = 3 moles
Since each molecule of H2 contains 2 atoms of hydrogen, we can calculate the number of atoms of hydrogen as:
n(H) = 2 × n = 2 × 3 = 6
Therefore, there are 6 atoms of hydrogen in 67.2 L of H2 at STP.
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
At STP (standard temperature and pressure), the pressure is 1 atm and the temperature is 0°C or 273 K. The volume of 1 mole of any gas at STP is 22.4 L, which is also known as the molar volume.
Therefore, we can calculate the number of moles of H2 in 67.2 L at STP as follows:
n = V / Vm
where Vm is the molar volume of H2 at STP, which is 22.4 L/mol.
n = 67.2 L / 22.4 L/mol = 3 moles
Since each molecule of H2 contains 2 atoms of hydrogen, we can calculate the number of atoms of hydrogen as:
n(H) = 2 × n = 2 × 3 = 6
Therefore, there are 6 atoms of hydrogen in 67.2 L of H2 at STP.
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Community Answer
How many atoms of hydrogen are in 67.2 L ofH2at STP?a)5.612 ×102...
No of moles=3 so... 3×avagadro number ×atomicity.becoz they are asking about atoms and H2 has 2 atoms so.. 3×6.023×10^23×2=3.6×10^24 this should be the answer but,there is no option at all.........????????
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