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A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperature of 60°C. It is dropped into 1kg water at 20°C. The final steady state temperature of water is:
- a)23.5°C
- b)300°C
- c)35°C
- d)40°C
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperatu...
Given:
Mass of steel ball, m = 1 kg
Specific heat of steel, C_s = 0.4 kJ/kg
Initial temperature of steel ball, T_s1 = 60°C
Mass of water, M_w = 1 kg
Initial temperature of water, T_w1 = 20°C
Final steady state temperature of water, T_w2 = ?
To find:
Final steady state temperature of water
Solution:
1. Heat lost by steel ball = Heat gained by water
i.e., m × C_s × (T_s1 - T_w2) = M_w × C_w × (T_w2 - T_w1)
where, C_w is the specific heat of water (taken as 4.18 kJ/kg°C)
2. On solving the above equation, we get:
T_w2 = (m × C_s × T_s1 + M_w × C_w × T_w1) / (m × C_s + M_w × C_w)
Substituting the given values, we get:
T_w2 = (1 × 0.4 × 60 + 1 × 4.18 × 20) / (1 × 0.4 + 1 × 4.18)
T_w2 = 23.5°C
Therefore, the final steady state temperature of water is 23.5°C.
Mass of steel ball, m = 1 kg
Specific heat of steel, C_s = 0.4 kJ/kg
Initial temperature of steel ball, T_s1 = 60°C
Mass of water, M_w = 1 kg
Initial temperature of water, T_w1 = 20°C
Final steady state temperature of water, T_w2 = ?
To find:
Final steady state temperature of water
Solution:
1. Heat lost by steel ball = Heat gained by water
i.e., m × C_s × (T_s1 - T_w2) = M_w × C_w × (T_w2 - T_w1)
where, C_w is the specific heat of water (taken as 4.18 kJ/kg°C)
2. On solving the above equation, we get:
T_w2 = (m × C_s × T_s1 + M_w × C_w × T_w1) / (m × C_s + M_w × C_w)
Substituting the given values, we get:
T_w2 = (1 × 0.4 × 60 + 1 × 4.18 × 20) / (1 × 0.4 + 1 × 4.18)
T_w2 = 23.5°C
Therefore, the final steady state temperature of water is 23.5°C.
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Community Answer
A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperatu...
Heat lost by hot body = Heat gained by cold body mhCph (th – tf) = mcCpc (tf – tc) gives tf = 23.5degreeC
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A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperature of 60°C. It is dropped into 1kg water at 20°C. The final steady state temperature of water is:a)23.5°Cb)300°Cc)35°Cd)40°CCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperature of 60°C. It is dropped into 1kg water at 20°C. The final steady state temperature of water is:a)23.5°Cb)300°Cc)35°Cd)40°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperature of 60°C. It is dropped into 1kg water at 20°C. The final steady state temperature of water is:a)23.5°Cb)300°Cc)35°Cd)40°CCorrect answer is option 'A'. Can you explain this answer?.
A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperature of 60°C. It is dropped into 1kg water at 20°C. The final steady state temperature of water is:a)23.5°Cb)300°Cc)35°Cd)40°CCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperature of 60°C. It is dropped into 1kg water at 20°C. The final steady state temperature of water is:a)23.5°Cb)300°Cc)35°Cd)40°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperature of 60°C. It is dropped into 1kg water at 20°C. The final steady state temperature of water is:a)23.5°Cb)300°Cc)35°Cd)40°CCorrect answer is option 'A'. Can you explain this answer?.
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A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperature of 60°C. It is dropped into 1kg water at 20°C. The final steady state temperature of water is:a)23.5°Cb)300°Cc)35°Cd)40°CCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperature of 60°C. It is dropped into 1kg water at 20°C. The final steady state temperature of water is:a)23.5°Cb)300°Cc)35°Cd)40°CCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A steel ball of mass 1kg and specific heat 0.4 kJ/kg is at a temperature of 60°C. It is dropped into 1kg water at 20°C. The final steady state temperature of water is:a)23.5°Cb)300°Cc)35°Cd)40°CCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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