Class 12 Exam  >  Class 12 Questions  >  (i) CH3–CH2–Br + NaOHCH3–CH... Start Learning for Free
(i) CH3 – CH2 – Br + NaOH  CH3 – CH2 – OH + NaBr → reaction ... (i)
(ii)  + NaOH  (CH3)C – CH2 – OH + NaBr → reaction ... (ii)
K1 & K2 are rate constant for above reaction correct relation is
  • a)
    K1 = K2
  • b)
    K1 > K2 
  • c)
    K1 < K2
  • d)
    K1 << K2
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
(i) CH3–CH2–Br + NaOHCH3–CH2–OH + NaBr →...
Option B is correct because in first reaction there is less steric hindrance as compared to second reaction so there is fast attack of reagent on the reactant in first reaction as compared to the second reaction
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Community Answer
(i) CH3–CH2–Br + NaOHCH3–CH2–OH + NaBr →...


This reaction is not proceed in forward direction.
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(i) CH3–CH2–Br + NaOHCH3–CH2–OH + NaBr →reaction ... (i)(ii)+ NaOH(CH3)3C –CH2–OH + NaBr →reaction ... (ii)K1& K2are rate constant for above reaction correct relation isa)K1= K2b)K1> K2c)K1< K2d)K1<< K2Correct answer is option 'B'. Can you explain this answer?
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