Class 11 Exam  >  Class 11 Questions  >  If in the hydrogen atom P.E. at ∞ is ch... Start Learning for Free
If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1st orbit of H-atom is __________ .
  • a)
    Zero
  • b)
    1
  • c)
    2
  • d)
    3
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then ...
Zero
Refrence level is Ist orbit
itself T. E. = 0
Ratio becomes zero
View all questions of this test
Most Upvoted Answer
If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then ...
In real the energy of electron in first orbit is -13.7 eV As a reference at infinity the energy of electron is 0 So if we choose the energy of electron at infinity 13.7 eV then 13.7 will be added to all energies because we recently used 'energy at infinity is 0' as a reference. Changing reference will affect all other values So finally electon's energy in 1st orbit=13.7 eV -13.7eV=0=K.E.
Free Test
Community Answer
If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then ...
Generally pE1st orbit -13.6 and PE of infinite is taken zero. since PE difference is constant. so if we take PE of infinite as 13.6 than PE of 1st orbit will be zero. hence ratio will be also zero.
Explore Courses for Class 11 exam

Top Courses for Class 11

Question Description
If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1storbit of H-atom is __________ .a)Zerob)1c)2d)3Correct answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1storbit of H-atom is __________ .a)Zerob)1c)2d)3Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1storbit of H-atom is __________ .a)Zerob)1c)2d)3Correct answer is option 'A'. Can you explain this answer?.
Solutions for If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1storbit of H-atom is __________ .a)Zerob)1c)2d)3Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1storbit of H-atom is __________ .a)Zerob)1c)2d)3Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1storbit of H-atom is __________ .a)Zerob)1c)2d)3Correct answer is option 'A'. Can you explain this answer?, a detailed solution for If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1storbit of H-atom is __________ .a)Zerob)1c)2d)3Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1storbit of H-atom is __________ .a)Zerob)1c)2d)3Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice If in the hydrogen atom P.E. at ∞ is choosen to be 13.6 eV then the ratio of T.E. to K.E. for 1storbit of H-atom is __________ .a)Zerob)1c)2d)3Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 11 tests.
Explore Courses for Class 11 exam

Top Courses for Class 11

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev