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To form a composite 16 μF, 1000V capacitor from a supply of identical capacitors marked 8 μF, 250 V, we require a minimum number of capacitors.
Correct answer is '32'. Can you explain this answer?
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To form a composite 16 μF, 1000Vcapacitor from a supply of identica...
To form a composite 16 µF, 1000V capacitor using 8 µF, 250V capacitors, we must consider both capacitance and voltage ratings.
Capacitance Calculation
- The required capacitance is 16 µF.
- Each capacitor has a capacitance of 8 µF.
- To achieve a total capacitance of 16 µF, we can connect two 8 µF capacitors in parallel:
- Total Capacitance in Parallel = C1 + C2 = 8 µF + 8 µF = 16 µF.
Thus, we need 2 capacitors in parallel to achieve the desired capacitance.
Voltage Rating Calculation
- Each capacitor is rated for 250V.
- The desired capacitor must withstand 1000V.
- To handle higher voltages, we can connect the capacitors in series. In series, voltage ratings add up:
- Total Voltage in Series = V1 + V2 + V3 + ... = n * 250V.
To achieve a voltage rating of 1000V:
- n * 250V >= 1000V,
- n >= 4.
Thus, we need 4 capacitors in series to meet the voltage requirement.
Combining Capacitance and Voltage Requirements
- To construct a composite capacitor that meets both the capacitance and voltage requirements:
- Use 4 capacitors in series to achieve 1000V.
- Each series group (4 capacitors) provides a total capacitance of 2 µF (since in series, C = 1/(1/C1 + 1/C2 + ...)).
To achieve a total of 16 µF:
- We need to connect 8 groups of 4 capacitors in series in parallel:
- Total Capacitors = 8 groups * 4 capacitors/group = 32 capacitors.
Thus, the minimum number of 8 µF, 250V capacitors needed to form a 16 µF, 1000V capacitor is 32.
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To form a composite 16 μF, 1000Vcapacitor from a supply of identical capacitors marked 8 μF, 250 V, we require a minimum number of capacitors.Correct answer is '32'. Can you explain this answer?
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