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A sum of money doubles itself in 10 years at S.I. In how many years will it amount to 8 times itself.?
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A sum of money doubles itself in 10 years at S.I. In how many years wi...
Understanding Simple Interest (S.I.)
Simple Interest is calculated using the formula:
S.I. = (Principal × Rate × Time) / 100
In this scenario, we know that a sum of money doubles in 10 years at simple interest.
Calculating Rate of Interest
- Let the principal amount be P.
- The amount after 10 years = 2P.
- The interest earned in 10 years = 2P - P = P.
Using the simple interest formula:
P = (P × Rate × 10) / 100
- This simplifies to:
Rate = 10%.
Finding Time to Amount to 8 Times
Now, we need to determine how long it will take for the principal to amount to 8 times itself.
- Amount after 't' years = 8P.
- Interest earned = 8P - P = 7P.
Using the simple interest formula again:
7P = (P × 10 × t) / 100
- Simplifying gives us:
7 = (10t) / 100
- Thus, 700 = 10t
- Therefore, t = 70 years.
Conclusion
In conclusion, the time required for the sum of money to amount to 8 times itself at the same rate of interest is:
- 70 years.
This logical breakdown illustrates how simple interest functions and how time can be calculated based on the principal and rate of interest.
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A sum of money doubles itself in 10 years at S.I. In how many years will it amount to 8 times itself.?
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