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 Electrolytic reduction of alumina to aluminium by Hall–Heroult process is carried out :  [JEE 2000 Qualifying]
  • a)
     In the presence of NaCl
  • b)
     In the presence of fluorite
  • c)
     In the presence of cryolite which forms a melt with lower melting temperature.
  • d)
     In the presence of cryolite which forms a melt with higher melting temperature.
Correct answer is option 'C'. Can you explain this answer?
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Electrolytic reduction of alumina to aluminium by Hall–Heroult p...
Cryolite is Na3AlF6 .which brings down the temperature to be maintained while carrying out the electrolytic reduction of alumina from 2000 deg celsius to about 900 deg celsius
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A fuel cell is a cell that is continuously supplied with an oxidant and a reductant so that it can deliver a current indefinitely.Fuel cells offer the possibility of achieving high thermodynamic efficiency in the conversion of Gibbs energy into mechanical work. Internal combustion engines at best convert only the fraction (T2 T1)/T2 of the heat of combustion into mechanical work.While the thermodynamic efficiency of the fuel cell is given by, is theGibbs energy change for the cell reaction and H is the enthalpy change of the cell reaction.A hydrogen-oxygen fuel cell may have an acidic or alkaline electrolyte.Pt|H2(g)|H+(aq.)||H2O( l )|O2(g)|Pt; The above fuel cell is used to produce constant current supply under constant temperature 30 atm constant total pressure condition in a cylinder. If 10 moles H2 and 5 moles of O2 were taken initially. Rate of combustion of O2 is 10 milli moles per minute. The half cell reactions areTo maximize the power per unit mass of an electrochemical cell, the electronic and electrolytic resistances of the cell must be minimized. Since fused salts have lower electrolytic resistances than aqueous solutions, high-temperature electrochemical cells are of special interest for practical applications.Q.The above fuel cell is used completely as an electrolytic cell with Cu voltameter of resistance 26.94 W using Pt electrodes. Initially Cu voltameter contains 1 litre solution of 0.05M CuSO4.[H+] in solution after electrolysis (Assuming no change on volume of solution).

A fuel cell is a cell that is continuously supplied with an oxidant and a reductant so that it can deliver a current indefinitely.Fuel cells offer the possibility of achieving high thermodynamic efficiency in the conversion of Gibbs energy into mechanical work. Internal combustion engines at best convert only the fraction (T2 T1)/T2 of the heat of combustion into mechanical work.While the thermodynamic efficiency of the fuel cell is given by, is theGibbs energy change for the cell reaction and H is the enthalpy change of the cell reaction.A hydrogen-oxygen fuel cell may have an acidic or alkaline electrolyte.Pt|H2(g)|H+(aq.)||H2O( l )|O2(g)|Pt; The above fuel cell is used to produce constant current supply under constant temperature 30 atm constant total pressure condition in a cylinder. If 10 moles H2 and 5 moles of O2 were taken initially. Rate of combustion of O2 is 10 milli moles per minute. The half cell reactions areTo maximize the power per unit mass of an electrochemical cell, the electronic and electrolytic resistances of the cell must be minimized. Since fused salts have lower electrolytic resistances than aqueous solutions, high-temperature electrochemical cells are of special interest for practical applications.Q.If m(Cu2+) = 0.01S m2 mole -1, m (H+) = 0.035 S m2 mole-1 and m (SO42-) = 0.016 S m2 mole-1, specific conductivity of resulting solution left in sopper voltameter after above electrolysis is

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Electrolytic reduction of alumina to aluminium by Hall–Heroult process is carried out : [JEE 2000 Qualifying]a)In the presence of NaClb)In the presence of fluoritec)In the presence of cryolite which forms a melt with lower melting temperature.d)In the presence of cryolite which forms a melt with higher melting temperature.Correct answer is option 'C'. Can you explain this answer?
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Electrolytic reduction of alumina to aluminium by Hall–Heroult process is carried out : [JEE 2000 Qualifying]a)In the presence of NaClb)In the presence of fluoritec)In the presence of cryolite which forms a melt with lower melting temperature.d)In the presence of cryolite which forms a melt with higher melting temperature.Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Electrolytic reduction of alumina to aluminium by Hall–Heroult process is carried out : [JEE 2000 Qualifying]a)In the presence of NaClb)In the presence of fluoritec)In the presence of cryolite which forms a melt with lower melting temperature.d)In the presence of cryolite which forms a melt with higher melting temperature.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Electrolytic reduction of alumina to aluminium by Hall–Heroult process is carried out : [JEE 2000 Qualifying]a)In the presence of NaClb)In the presence of fluoritec)In the presence of cryolite which forms a melt with lower melting temperature.d)In the presence of cryolite which forms a melt with higher melting temperature.Correct answer is option 'C'. Can you explain this answer?.
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