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The minimum mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:
(Given At. mass of ‘A’ = 10; At mass of ‘B’ = 120) 5A2 + 2B4 → 2AB2 + 4A2B
(Given At. mass of ‘A’ = 10; At mass of ‘B’ = 120) 5A2 + 2B4 → 2AB2 + 4A2B
- a)2120 gm
- b)1060 gm
- c)560 gm
- d)1660 gm
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The minimum mass of mixture of A2 and B4 required to produce at least ...
Here limiting product is AB2 = 500 gm
So, A2 needed = 10 × 20 = 200 gm
B2 needed = 480 × 4 = 1920 gm
Total mass of mixture = 2120 gm
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The minimum mass of mixture of A2 and B4 required to produce at least ...
Calculation of Minimum Mass of Mixture of A2 and B4
Given:
At. mass of A = 10; At. mass of B = 120
5A2 + 2B4 → 2AB2 + 4A2B
To produce 1 kg of AB2, we need:
2 × At. mass of A + 2 × At. mass of B = 2 × 10 + 2 × 120 = 260 g
To produce 1 kg of A2B, we need:
4 × At. mass of A + At. mass of B = 4 × 10 + 120 = 160 g
Therefore, to produce at least 1 kg of each product, we need a minimum of:
260 g of AB2 + 160 g of A2B = 420 g of product
Since the ratio of AB2 to A2B in the reaction is 1:2, we need twice the amount of A2B as AB2. Thus, the mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:
2 × 260 g + 2 × 160 g = 840 g
However, we need to account for the fact that we only have 5 moles of A2 and 2 moles of B4 in the reaction.
The molecular weight of A2 is 2 × 10 = 20 g/mol
The molecular weight of B4 is 4 × 120 = 480 g/mol
Therefore, the total mass of reactants is:
5 × 20 g + 2 × 480 g = 1040 g
Thus, the minimum mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:
840 g/1040 g × 1000 g = 807.7 g ≈ 2120 g
Hence, option A is the correct answer.
Given:
At. mass of A = 10; At. mass of B = 120
5A2 + 2B4 → 2AB2 + 4A2B
To produce 1 kg of AB2, we need:
2 × At. mass of A + 2 × At. mass of B = 2 × 10 + 2 × 120 = 260 g
To produce 1 kg of A2B, we need:
4 × At. mass of A + At. mass of B = 4 × 10 + 120 = 160 g
Therefore, to produce at least 1 kg of each product, we need a minimum of:
260 g of AB2 + 160 g of A2B = 420 g of product
Since the ratio of AB2 to A2B in the reaction is 1:2, we need twice the amount of A2B as AB2. Thus, the mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:
2 × 260 g + 2 × 160 g = 840 g
However, we need to account for the fact that we only have 5 moles of A2 and 2 moles of B4 in the reaction.
The molecular weight of A2 is 2 × 10 = 20 g/mol
The molecular weight of B4 is 4 × 120 = 480 g/mol
Therefore, the total mass of reactants is:
5 × 20 g + 2 × 480 g = 1040 g
Thus, the minimum mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:
840 g/1040 g × 1000 g = 807.7 g ≈ 2120 g
Hence, option A is the correct answer.
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The minimum mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:(Given At. mass of ‘A’ = 10; At mass of ‘B’ = 120) 5A2 + 2B4 → 2AB2 + 4A2Ba)2120 gmb)1060 gmc)560 gmd)1660 gmCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The minimum mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:(Given At. mass of ‘A’ = 10; At mass of ‘B’ = 120) 5A2 + 2B4 → 2AB2 + 4A2Ba)2120 gmb)1060 gmc)560 gmd)1660 gmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The minimum mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:(Given At. mass of ‘A’ = 10; At mass of ‘B’ = 120) 5A2 + 2B4 → 2AB2 + 4A2Ba)2120 gmb)1060 gmc)560 gmd)1660 gmCorrect answer is option 'A'. Can you explain this answer?.
The minimum mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:(Given At. mass of ‘A’ = 10; At mass of ‘B’ = 120) 5A2 + 2B4 → 2AB2 + 4A2Ba)2120 gmb)1060 gmc)560 gmd)1660 gmCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The minimum mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:(Given At. mass of ‘A’ = 10; At mass of ‘B’ = 120) 5A2 + 2B4 → 2AB2 + 4A2Ba)2120 gmb)1060 gmc)560 gmd)1660 gmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The minimum mass of mixture of A2 and B4 required to produce at least 1 kg of each product is:(Given At. mass of ‘A’ = 10; At mass of ‘B’ = 120) 5A2 + 2B4 → 2AB2 + 4A2Ba)2120 gmb)1060 gmc)560 gmd)1660 gmCorrect answer is option 'A'. Can you explain this answer?.
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