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A body starts from rest, the ratio of distances travelled by the body during 3rd and 4thseconds is :
- a)7/5
- b)5/7
- c)7/3
- d)3/7
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A body starts from rest, the ratio of distances travelled by the body ...
The velocity after 2 sec = 2a and velocity after 3 sec = 3a
For some constant acceleration a,
Now distance travelled in third second, s3 = 2a + ½ a
= 5/2 a
Similarly distance travelled in fourth second, s4= 3a + ½ a
= 7/2 a
Hence the reqiuired ratio is 5/7
For some constant acceleration a,
Now distance travelled in third second, s3 = 2a + ½ a
= 5/2 a
Similarly distance travelled in fourth second, s4= 3a + ½ a
= 7/2 a
Hence the reqiuired ratio is 5/7
Most Upvoted Answer
A body starts from rest, the ratio of distances travelled by the body ...
In question its asked about ratio of distance travelled in 3rd second & distance travelled in 4th second..
In this case; we have the formula;
Sn=u+a(n-1/2)..
S3=0+a(3-1/2)..
S3=a(6-1/2)..
S3=a(5/2)..
S4=u+a(4-1/2)..
S4=0+a(4-1/2)..
S4=a(7/2)..
S3/S4=a(5/2)/a(7/2)..
S3/S4=5/7..
Hence;option B is true...
In this case; we have the formula;
Sn=u+a(n-1/2)..
S3=0+a(3-1/2)..
S3=a(6-1/2)..
S3=a(5/2)..
S4=u+a(4-1/2)..
S4=0+a(4-1/2)..
S4=a(7/2)..
S3/S4=a(5/2)/a(7/2)..
S3/S4=5/7..
Hence;option B is true...
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Community Answer
A body starts from rest, the ratio of distances travelled by the body ...
Solution:
Given, the body starts from rest.
Let, s1 and s2 be the distances travelled by the body in the 3rd and 4th seconds respectively.
Using the formula, s=ut+1/2at^2, where u= initial velocity=0, a= acceleration=9.8 m/s^2 (constant)
We get, s1=1/2×9.8×(3)^2=44.1m and s2=1/2×9.8×(4)^2=78.4m
Therefore, the ratio of distances travelled by the body during 3rd and 4th seconds is
s2/s1=78.4/44.1=5/7
Hence, option B is the correct answer.
Answer: The correct option is B) 5/7.
Explanation:
Given, the body starts from rest.
Let, s1 and s2 be the distances travelled by the body in the 3rd and 4th seconds respectively.
Using the formula, s=ut+1/2at^2, where u= initial velocity=0, a= acceleration=9.8 m/s^2 (constant)
We get, s1=1/2×9.8×(3)^2=44.1m and s2=1/2×9.8×(4)^2=78.4m
Therefore, the ratio of distances travelled by the body during 3rd and 4th seconds is
s2/s1=78.4/44.1=5/7
Hence, option B is the correct answer.
Given, the body starts from rest.
Let, s1 and s2 be the distances travelled by the body in the 3rd and 4th seconds respectively.
Using the formula, s=ut+1/2at^2, where u= initial velocity=0, a= acceleration=9.8 m/s^2 (constant)
We get, s1=1/2×9.8×(3)^2=44.1m and s2=1/2×9.8×(4)^2=78.4m
Therefore, the ratio of distances travelled by the body during 3rd and 4th seconds is
s2/s1=78.4/44.1=5/7
Hence, option B is the correct answer.
Answer: The correct option is B) 5/7.
Explanation:
Given, the body starts from rest.
Let, s1 and s2 be the distances travelled by the body in the 3rd and 4th seconds respectively.
Using the formula, s=ut+1/2at^2, where u= initial velocity=0, a= acceleration=9.8 m/s^2 (constant)
We get, s1=1/2×9.8×(3)^2=44.1m and s2=1/2×9.8×(4)^2=78.4m
Therefore, the ratio of distances travelled by the body during 3rd and 4th seconds is
s2/s1=78.4/44.1=5/7
Hence, option B is the correct answer.
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A body starts from rest, the ratio of distances travelled by the body during 3rdand 4thseconds is :a)7/5b)5/7c)7/3d)3/7Correct answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body starts from rest, the ratio of distances travelled by the body during 3rdand 4thseconds is :a)7/5b)5/7c)7/3d)3/7Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body starts from rest, the ratio of distances travelled by the body during 3rdand 4thseconds is :a)7/5b)5/7c)7/3d)3/7Correct answer is option 'B'. Can you explain this answer?.
A body starts from rest, the ratio of distances travelled by the body during 3rdand 4thseconds is :a)7/5b)5/7c)7/3d)3/7Correct answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body starts from rest, the ratio of distances travelled by the body during 3rdand 4thseconds is :a)7/5b)5/7c)7/3d)3/7Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body starts from rest, the ratio of distances travelled by the body during 3rdand 4thseconds is :a)7/5b)5/7c)7/3d)3/7Correct answer is option 'B'. Can you explain this answer?.
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