Class 12 Exam  >  Class 12 Questions  >  The activation energies of two reactions are ... Start Learning for Free
The activation energies of two reactions are given as Ea1= 40 J and Ea2= 80 J, then the relation between their rate constants can be written as:
  • a)
    k1 > k2
  • b)
    k1 < k2
  • c)
    k1 = k2
  • d)
    k1 + k= 0
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The activation energies of two reactions are given as Ea1= 40 J and Ea...
As the value of activation energy, Ea increases, the value of rate constant, k decreases.
 So, k1 > k2 since E1 < E2
Free Test
Community Answer
The activation energies of two reactions are given as Ea1= 40 J and Ea...
Explanation:

To understand the relation between the rate constants of two reactions with different activation energies, we need to refer to the Arrhenius equation. The Arrhenius equation relates the rate constant (k) of a reaction to the activation energy (Ea) and the temperature (T). The equation is given as:

k = A * e^(-Ea/RT)

Where:
- k is the rate constant
- A is the pre-exponential factor or frequency factor
- Ea is the activation energy
- R is the gas constant
- T is the temperature in Kelvin

Now, let's consider two reactions with activation energies Ea1 and Ea2. According to the Arrhenius equation, their rate constants k1 and k2 can be written as:

k1 = A1 * e^(-Ea1/RT)
k2 = A2 * e^(-Ea2/RT)

Relation between the Rate Constants:

To find the relation between k1 and k2, we can divide the two equations:

k1/k2 = (A1 * e^(-Ea1/RT)) / (A2 * e^(-Ea2/RT))

Now, let's simplify the equation. Since A1 and A2 are the pre-exponential factors and they do not depend on temperature or activation energy, we can cancel them out:

k1/k2 = e^(-Ea1/RT) / e^(-Ea2/RT)

To simplify the equation further, we can use the properties of exponents. When dividing two numbers with the same base, the exponents subtract:

k1/k2 = e^((-Ea1/RT) - (-Ea2/RT))
k1/k2 = e^(-Ea1/RT + Ea2/RT)

Now, let's simplify the exponents by combining like terms:

k1/k2 = e^((Ea2 - Ea1)/RT)

Since Ea2 > Ea1 (given in the question), the exponent (Ea2 - Ea1) is positive. Therefore, e^(positive) is always greater than 1.

Therefore, we can conclude that k1/k2 > 1, which means k1 is greater than k2. So, the correct relation between the rate constants is:

k1 > k2 (Option A)
Explore Courses for Class 12 exam

Top Courses for Class 12

Question Description
The activation energies of two reactions are given as Ea1= 40 J and Ea2= 80 J, then the relation between their rate constants can be written as:a)k1 > k2b)k1<k2c)k1 = k2d)k1+k2= 0Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The activation energies of two reactions are given as Ea1= 40 J and Ea2= 80 J, then the relation between their rate constants can be written as:a)k1 > k2b)k1<k2c)k1 = k2d)k1+k2= 0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The activation energies of two reactions are given as Ea1= 40 J and Ea2= 80 J, then the relation between their rate constants can be written as:a)k1 > k2b)k1<k2c)k1 = k2d)k1+k2= 0Correct answer is option 'A'. Can you explain this answer?.
Solutions for The activation energies of two reactions are given as Ea1= 40 J and Ea2= 80 J, then the relation between their rate constants can be written as:a)k1 > k2b)k1<k2c)k1 = k2d)k1+k2= 0Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of The activation energies of two reactions are given as Ea1= 40 J and Ea2= 80 J, then the relation between their rate constants can be written as:a)k1 > k2b)k1<k2c)k1 = k2d)k1+k2= 0Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The activation energies of two reactions are given as Ea1= 40 J and Ea2= 80 J, then the relation between their rate constants can be written as:a)k1 > k2b)k1<k2c)k1 = k2d)k1+k2= 0Correct answer is option 'A'. Can you explain this answer?, a detailed solution for The activation energies of two reactions are given as Ea1= 40 J and Ea2= 80 J, then the relation between their rate constants can be written as:a)k1 > k2b)k1<k2c)k1 = k2d)k1+k2= 0Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of The activation energies of two reactions are given as Ea1= 40 J and Ea2= 80 J, then the relation between their rate constants can be written as:a)k1 > k2b)k1<k2c)k1 = k2d)k1+k2= 0Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The activation energies of two reactions are given as Ea1= 40 J and Ea2= 80 J, then the relation between their rate constants can be written as:a)k1 > k2b)k1<k2c)k1 = k2d)k1+k2= 0Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam

Top Courses for Class 12

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev