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A card is drawn from each of two well-shuffled packs of cards.The probability that at least one of them is an ace is
- a)1/169
- b)25 /169
- c)2 /13
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A card is drawn from each of two well-shuffled packs of cards.The prob...
The probability of at least one ace
= 1 - (the probability of no aces)
= 1 - (48/52) (48/52) [each pack of 52 has 4 aces, so it has 48 cards that aren't aces]
= 1 - (12/13) (12/13) [in lowest terms]
= 1 - 144/169
= 25/169
Most Upvoted Answer
A card is drawn from each of two well-shuffled packs of cards.The prob...
Solution:
Two well-shuffled packs of cards have a total of 104 cards, out of which 8 are aces (4 from each pack).
Let's find the probability that neither of the cards drawn is an ace:
Probability of drawing a non-ace from the first pack = 96/104
Probability of drawing a non-ace from the second pack = 96/104
Probability of drawing non-aces from both packs = (96/104) x (96/104) = 9216/10816
Therefore, the probability that at least one card is an ace = 1 - 9216/10816 = 900/10816 = 25/169.
Hence, option B is the correct answer.
Two well-shuffled packs of cards have a total of 104 cards, out of which 8 are aces (4 from each pack).
Let's find the probability that neither of the cards drawn is an ace:
Probability of drawing a non-ace from the first pack = 96/104
Probability of drawing a non-ace from the second pack = 96/104
Probability of drawing non-aces from both packs = (96/104) x (96/104) = 9216/10816
Therefore, the probability that at least one card is an ace = 1 - 9216/10816 = 900/10816 = 25/169.
Hence, option B is the correct answer.
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A card is drawn from each of two well-shuffled packs of cards.The prob...
The H.M of 1,6,8 is
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A card is drawn from each of two well-shuffled packs of cards.The probability that at least one of them is an ace isa)1/169b)25 /169c)2 /13d)None of theseCorrect answer is option 'B'. Can you explain this answer?
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