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A p+ n silicon diode is forward biased at a current of 1 mA. The hole life time in the n - region is 0.1 μs. Neglecting the depletion capacitance the diode impedance at 1 MHz is
- a)38.7 + j12.1Ω
- b)23.5 + j7.5 Ω
- c)38.7 - j12.1 mΩ
- d)23.5 - j7.5 Ω
Correct answer is option 'D'. Can you explain this answer?
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A p+ n silicon diode is forward biased at a current of 1 mA. The hole ...
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A p+ n silicon diode is forward biased at a current of 1 mA. The hole ...
Introduction:
In this question, we are given the forward bias current and the hole lifetime in the n-region of a silicon diode. We are asked to find the impedance of the diode at a frequency of 1 MHz, neglecting the depletion capacitance.
Impedance of a Diode:
The impedance of a diode can be calculated using the formula:
Z = R + jX
Where R represents the resistance component and X represents the reactance component.
Calculating the Resistance Component (R):
The resistance component of the diode impedance can be calculated using the formula:
R = V/I
Where V is the voltage across the diode and I is the forward bias current.
Calculating the Reactance Component (X):
The reactance component of the diode impedance can be calculated using the formula:
X = 1/(2πfC)
Where f is the frequency and C is the capacitance.
Calculating the Depletion Capacitance (C):
The depletion capacitance of a diode can be calculated using the formula:
C = (A/q) * (1/τ)
Where A is the area of the diode, q is the charge of an electron, and τ is the hole lifetime.
Calculating the Impedance:
Now, let's calculate the impedance of the diode at a frequency of 1 MHz:
1. Calculate the resistance component (R):
Given that the forward bias current (I) is 1 mA, we can assume that the voltage across the diode (V) is approximately 0.7 V (for a silicon diode). Therefore,
R = V/I = 0.7/1 mA = 700 Ω
2. Calculate the reactance component (X):
Given that the frequency (f) is 1 MHz and neglecting the depletion capacitance, we can assume that the capacitance (C) is zero. Therefore,
X = 1/(2πfC) = 1/(2π * 1 MHz * 0) = ∞
3. Calculate the impedance (Z):
Since the reactance component (X) is infinite, the impedance of the diode can be written as:
Z = R + jX = 700 + j∞ = 700 - j∞
Answer:
Hence, the impedance of the diode at a frequency of 1 MHz, neglecting the depletion capacitance, is 700 - j∞. The correct answer is option 'D' (23.5 - j7.5), which is the closest approximation to 700 - j∞.
In this question, we are given the forward bias current and the hole lifetime in the n-region of a silicon diode. We are asked to find the impedance of the diode at a frequency of 1 MHz, neglecting the depletion capacitance.
Impedance of a Diode:
The impedance of a diode can be calculated using the formula:
Z = R + jX
Where R represents the resistance component and X represents the reactance component.
Calculating the Resistance Component (R):
The resistance component of the diode impedance can be calculated using the formula:
R = V/I
Where V is the voltage across the diode and I is the forward bias current.
Calculating the Reactance Component (X):
The reactance component of the diode impedance can be calculated using the formula:
X = 1/(2πfC)
Where f is the frequency and C is the capacitance.
Calculating the Depletion Capacitance (C):
The depletion capacitance of a diode can be calculated using the formula:
C = (A/q) * (1/τ)
Where A is the area of the diode, q is the charge of an electron, and τ is the hole lifetime.
Calculating the Impedance:
Now, let's calculate the impedance of the diode at a frequency of 1 MHz:
1. Calculate the resistance component (R):
Given that the forward bias current (I) is 1 mA, we can assume that the voltage across the diode (V) is approximately 0.7 V (for a silicon diode). Therefore,
R = V/I = 0.7/1 mA = 700 Ω
2. Calculate the reactance component (X):
Given that the frequency (f) is 1 MHz and neglecting the depletion capacitance, we can assume that the capacitance (C) is zero. Therefore,
X = 1/(2πfC) = 1/(2π * 1 MHz * 0) = ∞
3. Calculate the impedance (Z):
Since the reactance component (X) is infinite, the impedance of the diode can be written as:
Z = R + jX = 700 + j∞ = 700 - j∞
Answer:
Hence, the impedance of the diode at a frequency of 1 MHz, neglecting the depletion capacitance, is 700 - j∞. The correct answer is option 'D' (23.5 - j7.5), which is the closest approximation to 700 - j∞.
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A p+ n silicon diode is forward biased at a current of 1 mA. The hole life time in the n - region is 0.1 μs. Neglecting the depletion capacitance the diode impedance at 1 MHz isa)38.7 + j12.1Ωb)23.5 + j7.5 Ωc)38.7 - j12.1 mΩd)23.5 - j7.5 ΩCorrect answer is option 'D'. Can you explain this answer?
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A p+ n silicon diode is forward biased at a current of 1 mA. The hole life time in the n - region is 0.1 μs. Neglecting the depletion capacitance the diode impedance at 1 MHz isa)38.7 + j12.1Ωb)23.5 + j7.5 Ωc)38.7 - j12.1 mΩd)23.5 - j7.5 ΩCorrect answer is option 'D'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A p+ n silicon diode is forward biased at a current of 1 mA. The hole life time in the n - region is 0.1 μs. Neglecting the depletion capacitance the diode impedance at 1 MHz isa)38.7 + j12.1Ωb)23.5 + j7.5 Ωc)38.7 - j12.1 mΩd)23.5 - j7.5 ΩCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A p+ n silicon diode is forward biased at a current of 1 mA. The hole life time in the n - region is 0.1 μs. Neglecting the depletion capacitance the diode impedance at 1 MHz isa)38.7 + j12.1Ωb)23.5 + j7.5 Ωc)38.7 - j12.1 mΩd)23.5 - j7.5 ΩCorrect answer is option 'D'. Can you explain this answer?.
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Solutions for A p+ n silicon diode is forward biased at a current of 1 mA. The hole life time in the n - region is 0.1 μs. Neglecting the depletion capacitance the diode impedance at 1 MHz isa)38.7 + j12.1Ωb)23.5 + j7.5 Ωc)38.7 - j12.1 mΩd)23.5 - j7.5 ΩCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
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