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An oil of specific gravity 0.9 has viscosity of 0.28 Strokes at 380C.What will be its viscosity in Ns/m2
  • a)
    0.2520
  • b)
    0.0311
  • c)
    0.0252
  • d)
    0.0206
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
An oil of specific gravity 0.9 has viscosity of 0.28 Strokes at 380C.W...
Ans. (c) Specific Gravity = 0.9 therefore Density = 0.9 × 1000 =900 kg/m3
One Stoke = 10-4 m2/s
Viscosity (μ) = ρν
= 900 × 0.28 × 10-4 = 0.0252 Ns/m2
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Most Upvoted Answer
An oil of specific gravity 0.9 has viscosity of 0.28 Strokes at 380C.W...
Given data:
Specific gravity of oil, S = 0.9
Viscosity of oil at 38°C, μ = 0.28 Strokes
Density of oil, ρ = S × ρw (where ρw is the density of water at 4°C)

Calculation:
Density of water at 4°C, ρw = 1000 kg/m³
Density of oil, ρ = 0.9 × 1000 = 900 kg/m³
Dynamic viscosity of oil, μ = 0.28 Strokes = 0.028 Pa.s
Kinematic viscosity of oil, ν = μ/ρ = 0.028/900 = 3.11 × 10^-5 m²/s
Viscosity in Ns/m², η = ρ × ν = 900 × 3.11 × 10^-5 = 0.0252 Ns/m²

Therefore, the viscosity of the oil in Ns/m² is 0.0252 Ns/m², which is option C.
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An oil of specific gravity 0.9 has viscosity of 0.28 Strokes at 380C.W...
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