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Stability order of the following resonating structure will be:



  • a)
    I > II > III > IV
  • b)
    II > I > III > IV
  • c)
    III > II > I > IV
  • d)
    I > III > II > IV
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Stability order of the following resonating structure will be:a)I >...
-1st is uncharged so it is the most stable among the following options.
-2nd one is charged but have more no of covalent bonds than 3rd and 4th so it is more stable than 3rd and 4th.
-Between 3rd and 4th follow the electronegativity rulle which means more electronegative atom bears negative charge. In 4th the positive charge on oxygen atom is against the electronegative prinicple . So it will like to have negative charge rather than positive chargee. So 3rd is more stable tha 4th.
Therefore the order will be 1>2>3>4
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Most Upvoted Answer
Stability order of the following resonating structure will be:a)I >...
Ist is uncharged so the most stable among foolowing..2nd one is charged but have more no of covalent bond than 3rd and 4th so it is more stable than 3rd and 4th now b/w 3rd and 4th follow the electronegativity ruke which means more electronegative atom bears negative charge..in 4th the positive charge on oxygen atom against the electronegative prinicple ..as oxygen is a electronegative atom so it will like to have negative charge rather tha positive chargee..so 3rd is more stable tha 4th So order will be 1>2>3>4
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Community Answer
Stability order of the following resonating structure will be:a)I >...
First see 1,w/o charge 2nd most no pi bond third ,negtv charge on most electro- ve atom ,third charge seperation thrfor answer is 1
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Stability order of the following resonating structure will be:a)I > II > III > IVb)II > I > III > IVc)III > II > I > IVd)I > III > II > IVCorrect answer is option 'A'. Can you explain this answer?
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