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560 ml of 0.1 0 molarity NaOH is mixed with 440 ml of 0.25 molarity HCL solution in a thermos flask.head involved in the neutralization reaction is absorb by solution use delta as neutralization is equals to minus 57 kilo joule per ml density of a solution is equal to 1 gram per mole and specific heat of water is equals to 4.2 joule came - 1g - 1 negative minus 2 degree Celsius find the value of x?
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560 ml of 0.1 0 molarity NaOH is mixed with 440 ml of 0.25 molarity HC...
Understanding the Reaction
In this problem, we have a neutralization reaction between NaOH and HCl. The heat released during the reaction is absorbed by the solution, which can be calculated using the specific heat formula.
Step 1: Determine Moles of Reactants
- Molarity of NaOH = 0.10 mol/L
- Volume of NaOH = 560 ml = 0.560 L
- Moles of NaOH = 0.10 * 0.560 = 0.056 moles
- Molarity of HCl = 0.25 mol/L
- Volume of HCl = 440 ml = 0.440 L
- Moles of HCl = 0.25 * 0.440 = 0.110 moles
Step 2: Determine Limiting Reactant
- The reaction between NaOH and HCl is a 1:1 ratio.
- NaOH is the limiting reactant (0.056 moles < 0.110="" />
Step 3: Calculate Heat Released
- Heat released (q) = moles of NaOH * ΔH
- ΔH (neutralization) = -57 kJ/mol
- q = 0.056 * (-57) = -3.192 kJ = -3192 J
Step 4: Calculate the Total Mass of the Solution
- Total volume = 560 ml + 440 ml = 1000 ml
- Density = 1 g/ml
- Mass = 1000 g
Step 5: Calculate Temperature Change
Using the formula:
q = m * c * ΔT
- q = -3192 J
- m = 1000 g
- c = 4.2 J/g°C
Rearranging for ΔT:
ΔT = q / (m * c) = -3192 / (1000 * 4.2)
ΔT = -0.76°C
Conclusion
The temperature change (x) after the neutralization reaction is approximately -0.76°C.
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560 ml of 0.1 0 molarity NaOH is mixed with 440 ml of 0.25 molarity HCL solution in a thermos flask.head involved in the neutralization reaction is absorb by solution use delta as neutralization is equals to minus 57 kilo joule per ml density of a solution is equal to 1 gram per mole and specific heat of water is equals to 4.2 joule came - 1g - 1 negative minus 2 degree Celsius find the value of x?
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560 ml of 0.1 0 molarity NaOH is mixed with 440 ml of 0.25 molarity HCL solution in a thermos flask.head involved in the neutralization reaction is absorb by solution use delta as neutralization is equals to minus 57 kilo joule per ml density of a solution is equal to 1 gram per mole and specific heat of water is equals to 4.2 joule came - 1g - 1 negative minus 2 degree Celsius find the value of x? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 560 ml of 0.1 0 molarity NaOH is mixed with 440 ml of 0.25 molarity HCL solution in a thermos flask.head involved in the neutralization reaction is absorb by solution use delta as neutralization is equals to minus 57 kilo joule per ml density of a solution is equal to 1 gram per mole and specific heat of water is equals to 4.2 joule came - 1g - 1 negative minus 2 degree Celsius find the value of x? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 560 ml of 0.1 0 molarity NaOH is mixed with 440 ml of 0.25 molarity HCL solution in a thermos flask.head involved in the neutralization reaction is absorb by solution use delta as neutralization is equals to minus 57 kilo joule per ml density of a solution is equal to 1 gram per mole and specific heat of water is equals to 4.2 joule came - 1g - 1 negative minus 2 degree Celsius find the value of x?.
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