**Evaluation of f(x)**

To evaluate the given function f(x) = x^2 - 5x + 7, we substitute the given values into the function and calculate the result.

1. Evaluating f(2):
Substitute x = 2 into the function:
f(2) = (2)^2 - 5(2) + 7
= 4 - 10 + 7
= 1

2. Evaluating f(-1):
Substitute x = -1 into the function:
f(-1) = (-1)^2 - 5(-1) + 7
= 1 + 5 + 7
= 13

3. Evaluating f(1/3):
Substitute x = 1/3 into the function:
f(1/3) = (1/3)^2 - 5(1/3) + 7
= 1/9 - 5/3 + 7
= -52/9

Therefore, f(2) = 1, f(-1) = 13, and f(1/3) = -52/9.

**Evaluation of f(2) - f(-1) + f(1/3)**

To evaluate f(2) - f(-1) + f(1/3), we substitute the previously calculated values into the expression and calculate the result.

f(2) - f(-1) + f(1/3) = (1) - (13) + (-52/9)
= 1 - 13 - (52/9)
= -12 - (52/9)
= -108/9 - 52/9
= -160/9

Therefore, f(2) - f(-1) + f(1/3) = -160/9.

**Explanation:**

The given function f(x) = x^2 - 5x + 7 is a polynomial function of degree 2. To evaluate the function at a specific value, we substitute that value in place of x and calculate the result.

In this case, we evaluate f(x) at x = 2, x = -1, and x = 1/3 by substituting these values into the function. By performing the necessary calculations, we find that f(2) = 1, f(-1) = 13, and f(1/3) = -52/9.

Next, we evaluate the expression f(2) - f(-1) + f(1/3) by substituting the previously calculated values. By performing the required calculations, we find that f(2) - f(-1) + f(1/3) = -160/9.

Therefore, the evaluation of f(2) - f(-1) + f(1/3) is -160/9.

F(x)=x^2-5x+7 ; f(2)=2^2-(5×2)+7=4-10+7=1 ; f(-1)=(-1)^2-5(-1)+7=1+5+7=13 ; f(1/3)=(1/3)^2-5(1/3)+7=(1/9)-(5/3)+7= (1-15+63)/9=49/9 ; Now, f(2)-f(-1)+f(1/3) = 1-13+(49/9)=(9-117+49)/9 =-(59/9) .. Ans..