A circular coil of radius r carries current I. The magnetic field at i...
As you know that magnetic field at point on the axis of current carrying ring is

where x is the point on the axis of ring, R is the radius of ring , i is the current carrying on ring and N is the number of turns .
This is possible only when x = +-√3R
Hence, √3R distance from the centre magnetic field is equal to magnetic field at centre .

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A circular coil of radius r carries current I. The magnetic field at i...
A circular coil of radius r carries current I. The magnetic field at i...
Introduction:
The question asks us to find the distance from the center of a circular coil on the axis of the coil where the magnetic field will be B/8. We are given that the coil has a radius of r and carries a current of I. The magnetic field at the center of the coil is B.
Explanation:
To solve this problem, we can make use of the formula for the magnetic field at the center of a circular coil, which is given by:
B = μ₀ * I / (2 * R)
where B is the magnetic field, μ₀ is the permeability of free space, I is the current, and R is the radius of the coil.
We are given that the magnetic field at the center is B. We need to find the distance from the center on the axis of the coil where the magnetic field will be B/8.
Step 1: Finding the magnetic field at the desired distance:
Let's assume that the distance from the center on the axis of the coil where the magnetic field is B/8 is x.
At this distance, the magnetic field can be calculated using the formula for the magnetic field on the axis of a circular coil, which is given by:
B' = μ₀ * I * R² / (2 * (R² + x²)^(3/2))
where B' is the magnetic field at the desired distance, μ₀ is the permeability of free space, I is the current, R is the radius of the coil, and x is the distance from the center on the axis of the coil.
Step 2: Equating the magnetic fields:
We can now equate the magnetic field at the center of the coil (B) to the magnetic field at the desired distance (B') and solve for x:
B = B'
μ₀ * I / (2 * R) = μ₀ * I * R² / (2 * (R² + x²)^(3/2))
Simplifying this equation, we get:
1 / R = R / (R² + x²)^(3/2)
Cross-multiplying and rearranging, we get:
(R² + x²)^(3/2) = R²
Taking the square root of both sides, we get:
R² + x² = R^(4/3)
Substituting x = 3R, we get:
R² + (3R)² = R^(4/3)
Simplifying this equation, we get:
R^(4/3) = 10R²
Taking the cube root of both sides, we get:
R^(4/3) = R^(2/3) * 10^(2/3)
Simplifying this equation, we get:
R^(2/3) = 10^(2/3)
Taking the cube of both sides, we get:
R^2 = 100
Taking the square root of both sides, we get:
R = 10
Therefore, the correct answer is option A) 3R.