Calculating Ionization Energy of Be3 Ion

Introduction
Ionization energy refers to the energy that is required to remove an electron from the ground state of an atom or ion. In this case, we are calculating the ionization energy of the Be3 ion with the electron in its ground state.

Formula
The formula for calculating the ionization energy of an atom or ion is:

IE = -RH*(Z^2 / n^2)

Where IE is the ionization energy, RH is the Rydberg constant, Z is the atomic number of the element, and n is the principal quantum number of the electron.

Steps to Calculate Ionization Energy of Be3 Ion

1. Identify the atomic number of beryllium. The atomic number of beryllium is 4.

2. Determine the number of electrons in the Be3 ion. Since Be3 ion has a charge of 3+, it means that it has lost three electrons. Therefore, the number of electrons in the Be3 ion is 1 (4 - 3 = 1).

3. Identify the principal quantum number of the electron in the ground state of the Be3 ion. The principal quantum number of the electron in the ground state of the Be3 ion is 1.

4. Calculate the ionization energy of the Be3 ion using the formula above. Plugging in the relevant values, we have:

IE = -RH*(Z^2 / n^2)
= -2.18 x 10^-18 J*(4^2 / 1^2)
= -2.18 x 10^-18 J*(16)
= -3.49 x 10^-17 J

5. Convert the ionization energy from joules to kilojoules per mole. Since one mole of Be3 ion contains 6.022 x 10^23 ions, we can convert the ionization energy from joules to kilojoules per mole by dividing by 1000 and multiplying by Avogadro's number. Therefore,

IE = -3.49 x 10^-17 J/ ion * (6.022 x 10^23 ion/ mol) / 1000 J/ KJ
= -2.10 x 10^4 KJ/ mol

Therefore, the ionization energy of the Be3 ion with the electron in its ground state is -21000 KJ /mol.

We know E= -1312.5×Z^2÷n^2 kJ/mol we can find energy for all one electron species with the help of H. ...for H E = -1312.5 ×1^2÷1^2 I.e -1312 kJ / mol and .. for Be^+3 it is E of H × ZBe^2 for same orbit I.e ....-1312.5 × 16 = -21000kJ / mol .............hope this would be helpful