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The sum of digits of a two digit number is 10. If 18 be subtracted from it the digits in the resulting number will be equal. The number is?
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The sum of digits of a two digit number is 10. If 18 be subtracted fro...
Understanding the Problem
To find the two-digit number that meets the conditions given, we need to analyze the clues provided:
1. Sum of Digits: The sum of the digits of the two-digit number equals 10.
2. Subtraction Result: When 18 is subtracted from this number, the resulting digits are equal.
Defining the Variables
Let the two-digit number be represented as 10a + b, where:
- a = the tens digit
- b = the units digit
Setting Up the Equations
From the problem, we can derive the following equations:
- Equation 1: a + b = 10
- Equation 2: (10a + b) - 18 = 10c + c (where c is the common digit after subtraction)
This simplifies to:
10a + b - 18 = 11c
Finding Solutions
Now, we can substitute Equation 1 into our equations:
1. From a + b = 10, we can express b as:
b = 10 - a
2. Substitute b into Equation 2:
10a + (10 - a) - 18 = 11c
Simplifying gives:
9a - 8 = 11c
Now we can test integer values for a (1 to 9):
- If a = 8:
9(8) - 8 = 72 - 8 = 64, which is not divisible by 11.
- If a = 7:
9(7) - 8 = 63 - 8 = 55, which gives c = 5.
Therefore, b = 10 - 7 = 3.
So, the number is:
73
Conclusion
The two-digit number that meets the conditions is 73.
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The sum of digits of a two digit number is 10. If 18 be subtracted from it the digits in the resulting number will be equal. The number is?
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