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Y is older than x by 7 years 15 years back x's age was 3/4 of y's age. Their present ages are?
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Y is older than x by 7 years 15 years back x's age was 3/4 of y's age....
Understanding the Problem
To find the present ages of X and Y, we start with the information given:
- Y is older than X by 7 years.
- 15 years ago, X's age was 3/4 of Y's age.
Setting Up the Equations
Let X's present age be X years.
Then, Y's present age is (X + 7) years.
Now, we consider their ages 15 years ago:
- X's age 15 years ago = X - 15
- Y's age 15 years ago = (X + 7) - 15 = X - 8
According to the problem, 15 years ago:
(X - 15) = (3/4) * (X - 8)
Solving the Equation
Now, we solve the equation:
1. Multiply both sides by 4 to eliminate the fraction:
4(X - 15) = 3(X - 8)
2. Expanding both sides:
4X - 60 = 3X - 24
3. Rearranging the equation:
4X - 3X = -24 + 60
X = 36
Now that we have X's age, we can find Y's age:
- Y = X + 7 = 36 + 7 = 43
Present Ages
- Present age of X: 36 years
- Present age of Y: 43 years
Conclusion
Thus, the present ages of X and Y are:
- X is 36 years old.
- Y is 43 years old.
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Y is older than x by 7 years 15 years back x's age was 3/4 of y's age. Their present ages are?
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