Class 12 Exam  >  Class 12 Questions  >  The rate law for a reaction between the subst... Start Learning for Free
The rate law for a reaction between the substances A and 8 is given by
rate = k[A]n [B]m
If concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would be 
  • a)
  • b)
    (m + n)
  • c)
    (n - m)
  • d)
    2(n-m)
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The rate law for a reaction between the substances A and 8 is given by...


View all questions of this test
Most Upvoted Answer
The rate law for a reaction between the substances A and 8 is given by...


Free Test
Community Answer
The rate law for a reaction between the substances A and 8 is given by...
Explore Courses for Class 12 exam
The rate law for a reaction between the substances A and 8 is given byrate = k[A]n [B]mIf concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would bea)b)(m + n)c)(n - m)d)2(n-m)Correct answer is option 'D'. Can you explain this answer?
Question Description
The rate law for a reaction between the substances A and 8 is given byrate = k[A]n [B]mIf concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would bea)b)(m + n)c)(n - m)d)2(n-m)Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The rate law for a reaction between the substances A and 8 is given byrate = k[A]n [B]mIf concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would bea)b)(m + n)c)(n - m)d)2(n-m)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rate law for a reaction between the substances A and 8 is given byrate = k[A]n [B]mIf concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would bea)b)(m + n)c)(n - m)d)2(n-m)Correct answer is option 'D'. Can you explain this answer?.
Solutions for The rate law for a reaction between the substances A and 8 is given byrate = k[A]n [B]mIf concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would bea)b)(m + n)c)(n - m)d)2(n-m)Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of The rate law for a reaction between the substances A and 8 is given byrate = k[A]n [B]mIf concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would bea)b)(m + n)c)(n - m)d)2(n-m)Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The rate law for a reaction between the substances A and 8 is given byrate = k[A]n [B]mIf concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would bea)b)(m + n)c)(n - m)d)2(n-m)Correct answer is option 'D'. Can you explain this answer?, a detailed solution for The rate law for a reaction between the substances A and 8 is given byrate = k[A]n [B]mIf concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would bea)b)(m + n)c)(n - m)d)2(n-m)Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of The rate law for a reaction between the substances A and 8 is given byrate = k[A]n [B]mIf concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would bea)b)(m + n)c)(n - m)d)2(n-m)Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The rate law for a reaction between the substances A and 8 is given byrate = k[A]n [B]mIf concentration of A is doubled and that of 8 is halved, the new rate as compared to the earlier rate would bea)b)(m + n)c)(n - m)d)2(n-m)Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev