v^2 = u^2 + 2as
, where v
is the final velocity, u
is the initial velocity, a
is the acceleration (which is -9.8m/s^2 for upward motion), and s
is the displacement (maximum height reached).0 = 20^2 - 2*9.8*s
s
, we get s = 20.41m
s = ut + 0.5at^2
, where t
is the time taken.20.41 = 20*t + 0.5*(-9.8)*t^2
t
, we get t = 2.09s
s = ut + 0.5at^2
, where u = 24m/s
and t = 2s
.s = 24*2 + 0.5*(-9.8)*2^2
s
, we get s = 19.2m
x
meters above the release point.2.09 - (x/20)
seconds (since the ball takes 2.09 seconds to reach 20.41m and travels x
meters less).2 - (x/24)
seconds (since the stone takes 2 seconds to reach 19.2m and travels x
meters less).
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