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Energy required to dissociate 4 g of gaseous hydrogen into free gaseous atoms is 208 kcal at 25°C . The bond energy of H-H bond will be:
  • a)
    104 kcal
  • b)
    10.4 kcal
  • c)
    1.04 kcal
  • d)
    1040 kcal
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Energy required to dissociate 4 g of gaseous hydrogen into free gaseou...
Bond enthalpy is defined as amount of energy required to break one mole of bonds of a particular type between atoms in gaseous state.
4/2 = 2 moles
208/2 = 104 kcal 
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Most Upvoted Answer
Energy required to dissociate 4 g of gaseous hydrogen into free gaseou...
Bond energy is the amount of energy required to break a bond and separate the atoms involved. In this case, we are given the energy required to dissociate 4 grams of gaseous hydrogen into free gaseous atoms, which is 208 kcal.

To find the bond energy of the H-H bond, we need to calculate the energy required to break one mole of H-H bonds.

1. Calculate the number of moles of hydrogen:
- The molar mass of hydrogen is 2 g/mol.
- Given that we have 4 grams of hydrogen, we can calculate the number of moles using the formula:
Moles = Mass / Molar mass
Moles = 4 g / 2 g/mol
Moles = 2 moles

2. Calculate the energy required to dissociate one mole of hydrogen:
- The given energy is for 4 grams of hydrogen, so we need to divide it by 2 to get the energy for 1 mole.
Energy for 1 mole = 208 kcal / 2
Energy for 1 mole = 104 kcal

3. Calculate the bond energy of the H-H bond:
- The bond energy is the energy required to dissociate one mole of the H-H bond.
Bond energy = Energy for 1 mole
Bond energy = 104 kcal

Therefore, the bond energy of the H-H bond is 104 kcal, which corresponds to option A.
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Energy required to dissociate 4 g of gaseous hydrogen into free gaseous atoms is 208 kcal at 25°C . The bond energy of H-H bond will be:a)104 kcalb)10.4 kcalc)1.04 kcald)1040 kcalCorrect answer is option 'A'. Can you explain this answer?
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