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Consider a sorted array of n elements. Let k inversions (swapping) have been performed on the sorted array and we want to sort it again to reverse effect of inversions. If K is very small in comparison to n, then which sorting technique will prove efficient for making again the list in sorted increasing order array.
- a)Selection Sort
- b)Insertion Sort
- c)Bubble Sort
- d)Quick Sort
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Consider a sorted array of n elements. Let k inversions (swapping) hav...
Insertion sort is directly proportional to number of inversions present in the list.
Most Upvoted Answer
Consider a sorted array of n elements. Let k inversions (swapping) hav...
Explanation:
To efficiently sort a partially sorted array where only k inversions have been performed, the most suitable sorting technique is Insertion Sort.
Insertion Sort:
Insertion Sort is a simple sorting algorithm that works by repeatedly inserting the current element into the already sorted subarray to its left. It is based on the idea of arranging cards in a hand.
Efficiency of Insertion Sort:
1. Time Complexity:
- In the worst case, when the array is completely reversed, Insertion Sort has a time complexity of O(n^2).
- However, in the best case scenario when the array is already sorted, Insertion Sort has a time complexity of O(n).
- In the given scenario, k inversions have been performed on the sorted array. Since k is very small in comparison to n, the array is almost sorted. Therefore, Insertion Sort will have a time complexity close to O(n).
2. Space Complexity:
- Insertion Sort has a space complexity of O(1) as it sorts the array in-place.
Why Insertion Sort is suitable for this scenario?
- Insertion Sort is suitable for this scenario because it performs well when the input array is already partially sorted or contains a small number of inversions.
- In this case, since only k inversions have been performed, Insertion Sort will efficiently sort the array in close to linear time.
- Other sorting techniques like Selection Sort, Bubble Sort, and Quick Sort have higher time complexities and are not as efficient for this scenario.
Therefore, the correct answer is option b) Insertion Sort.
To efficiently sort a partially sorted array where only k inversions have been performed, the most suitable sorting technique is Insertion Sort.
Insertion Sort:
Insertion Sort is a simple sorting algorithm that works by repeatedly inserting the current element into the already sorted subarray to its left. It is based on the idea of arranging cards in a hand.
Efficiency of Insertion Sort:
1. Time Complexity:
- In the worst case, when the array is completely reversed, Insertion Sort has a time complexity of O(n^2).
- However, in the best case scenario when the array is already sorted, Insertion Sort has a time complexity of O(n).
- In the given scenario, k inversions have been performed on the sorted array. Since k is very small in comparison to n, the array is almost sorted. Therefore, Insertion Sort will have a time complexity close to O(n).
2. Space Complexity:
- Insertion Sort has a space complexity of O(1) as it sorts the array in-place.
Why Insertion Sort is suitable for this scenario?
- Insertion Sort is suitable for this scenario because it performs well when the input array is already partially sorted or contains a small number of inversions.
- In this case, since only k inversions have been performed, Insertion Sort will efficiently sort the array in close to linear time.
- Other sorting techniques like Selection Sort, Bubble Sort, and Quick Sort have higher time complexities and are not as efficient for this scenario.
Therefore, the correct answer is option b) Insertion Sort.
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Consider a sorted array of n elements. Let k inversions (swapping) hav...
Option B
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Consider a sorted array of n elements. Let k inversions (swapping) have been performed on the sorted array and we want to sort it again to reverse effect of inversions. If K is very small in comparison to n, then which sorting technique will prove efficient for making again the list in sorted increasing order array.a)Selection Sortb)Insertion Sortc)Bubble Sortd)Quick SortCorrect answer is option 'B'. Can you explain this answer?
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