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Predict the output of following program. Note that fun() is public in base and private in derived.
class Base {
    public void foo() { System.out.println("Base"); }
}
 
class Derived extends Base {
    private void foo() { System.out.println("Derived"); } 
}
 
public class Main {
    public static void main(String args[]) {
        Base b = new Derived();
        b.foo();
    }
  • a)
    Base
  • b)
    Derived
  • c)
    Compiler Error
  • d)
    Runtime Error
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Predict the output of following program. Note that fun() is public in ...
It is compiler error to give more restrictive access to a derived class function which overrides a base class function.
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Predict the output of following program. Note that fun() is public in base and private in derived.class Base { public void foo() { System.out.println("Base"); }}class Derived extends Base { private void foo() { System.out.println("Derived"); }}public class Main { public static void main(String args[]) { Base b = new Derived(); b.foo(); }}a)Baseb)Derivedc)Compiler Errord)Runtime ErrorCorrect answer is option 'C'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about Predict the output of following program. Note that fun() is public in base and private in derived.class Base { public void foo() { System.out.println("Base"); }}class Derived extends Base { private void foo() { System.out.println("Derived"); }}public class Main { public static void main(String args[]) { Base b = new Derived(); b.foo(); }}a)Baseb)Derivedc)Compiler Errord)Runtime ErrorCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Predict the output of following program. Note that fun() is public in base and private in derived.class Base { public void foo() { System.out.println("Base"); }}class Derived extends Base { private void foo() { System.out.println("Derived"); }}public class Main { public static void main(String args[]) { Base b = new Derived(); b.foo(); }}a)Baseb)Derivedc)Compiler Errord)Runtime ErrorCorrect answer is option 'C'. Can you explain this answer?.
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