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An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers is
- a)0.5
- b)0.18
- c)0.12
- d)0.06
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
An examination consists of two papers, Paper 1 and Paper 2. The probab...
Understanding the Problem
To find the probability of a student failing both papers, we will use the information given about the probabilities of failing each paper and their conditional probabilities.
Given Probabilities
- Probability of failing Paper 1 (P(F1)) = 0.3
- Probability of failing Paper 2 (P(F2)) = 0.2
- Conditional probability of failing Paper 1 given failing Paper 2 (P(F1 | F2)) = 0.6
Using the Conditional Probability Formula
To find the probability of failing both papers (P(F1 ∩ F2)), we can use the formula:
P(F1 ∩ F2) = P(F2) * P(F1 | F2)
Calculating the Probability
1. Find P(F1 ∩ F2):
- Substitute the known values into the formula:
- P(F1 ∩ F2) = P(F2) * P(F1 | F2)
- P(F1 ∩ F2) = 0.2 * 0.6
2. Calculate:
- P(F1 ∩ F2) = 0.12
Conclusion
Thus, the probability of a student failing both Paper 1 and Paper 2 is 0.12.
The correct answer is option 'C'.
To find the probability of a student failing both papers, we will use the information given about the probabilities of failing each paper and their conditional probabilities.
Given Probabilities
- Probability of failing Paper 1 (P(F1)) = 0.3
- Probability of failing Paper 2 (P(F2)) = 0.2
- Conditional probability of failing Paper 1 given failing Paper 2 (P(F1 | F2)) = 0.6
Using the Conditional Probability Formula
To find the probability of failing both papers (P(F1 ∩ F2)), we can use the formula:
P(F1 ∩ F2) = P(F2) * P(F1 | F2)
Calculating the Probability
1. Find P(F1 ∩ F2):
- Substitute the known values into the formula:
- P(F1 ∩ F2) = P(F2) * P(F1 | F2)
- P(F1 ∩ F2) = 0.2 * 0.6
2. Calculate:
- P(F1 ∩ F2) = 0.12
Conclusion
Thus, the probability of a student failing both Paper 1 and Paper 2 is 0.12.
The correct answer is option 'C'.
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Community Answer
An examination consists of two papers, Paper 1 and Paper 2. The probab...
Let A be the event that ‘failed in paper 1’.
B be the event that ‘failed in paper 2’.
Given P(A) = 0.3, P(B) = 0.2.
To find the probability of failing in both papers (P(F1 ∩ F2)),
we use the formula for conditional probability: P(F1 | F2) = P(F1 ∩ F2) / P(F2).
Here, P(F1 | F2) = 0.6, and P(F2) = 0.2.
Therefore, P(F1 ∩ F2) = P(F1 | F2) × P(F2)
= 0.6 × 0.2 = 0.12.
Thus, the correct answer is option 3, with a probability of 0.12.
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An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers isa)0.5b)0.18c)0.12d)0.06Correct answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers isa)0.5b)0.18c)0.12d)0.06Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers isa)0.5b)0.18c)0.12d)0.06Correct answer is option 'C'. Can you explain this answer?.
An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers isa)0.5b)0.18c)0.12d)0.06Correct answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers isa)0.5b)0.18c)0.12d)0.06Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers isa)0.5b)0.18c)0.12d)0.06Correct answer is option 'C'. Can you explain this answer?.
Solutions for An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers isa)0.5b)0.18c)0.12d)0.06Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
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