Calculation of Stoichiometric Ratio

To determine the mass of CO2 produced from the given mixture of C2H4O2 and O2, we need to first calculate the stoichiometric ratio of the reactants. This can be done using the balanced chemical equation for the combustion of C2H4O2:

C2H4O2 + 3O2 → 2CO2 + 2H2O

From the equation, we can see that 1 mole of C2H4O2 reacts with 3 moles of O2 to produce 2 moles of CO2 and 2 moles of H2O. Therefore, the stoichiometric ratio of C2H4O2 to O2 is 1:3.

Calculation of Limiting Reactant

To determine the mass of CO2 produced, we need to identify the limiting reactant. The limiting reactant is the reactant that is completely consumed in the reaction, thereby limiting the amount of product that can be formed. To identify the limiting reactant, we need to calculate the amount of CO2 that can be produced from each reactant and compare them.

Let x be the amount of C2H4O2 (in grams) in the mixture and y be the amount of O2 (in grams) in the mixture. Then, we can write the following equations:

Amount of CO2 from C2H4O2 = (2/1) * (x/60) = x/30
Amount of CO2 from O2 = (2/3) * (y/32) = (y/48)

Since the stoichiometric ratio of C2H4O2 to O2 is 1:3, we can write:

x/y = 1/3
x = (1/3)*y

Substituting x in terms of y in the equation for CO2 from C2H4O2, we get:

Amount of CO2 from C2H4O2 = (1/30)*y

Now, we can compare the amounts of CO2 from each reactant:

Amount of CO2 from C2H4O2 = (1/30)*y
Amount of CO2 from O2 = (y/48)

The limiting reactant is the one that produces the least amount of CO2. Therefore, the limiting reactant is O2.

Calculation of Mass of CO2 Produced

The amount of CO2 produced from the limiting reactant (O2) can be calculated using the equation for CO2 from O2:

Amount of CO2 from O2 = (y/48)

Substituting y = 620 - x, we get:

Amount of CO2 from O2 = ((620 - x)/48)

To find the mass of CO2 produced, we need to multiply the amount of CO2 by its molar mass:

Mass of CO2 produced = ((620 - x)/48) * 44

Substituting x = (1/3)*y, we get:

x = (1/3)*(620 - x)
x = 206.67 - (1/3)*x
4/3*x = 206.67
x = 155

Therefore, the mass of C2H4O2 in the mixture is 155 g. Substituting x = 155 in the equation for

The mass of P4O10 produced if 440 gm of P4S3is mixed with 384 gm of O2is