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The population of a city was 40,000 in the year 1999. It increased at the rate of 10% p.a. Find the population at the end of the year 2000.
- a)35000
- b)44000
- c)40000
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The population of a city was 40,000 in the year 1999. It increased at ...
Population of the city in 1999 = 40,000 Percentage increased = 10% Therefore 10% of 40,000 = 10/100 × 40,000 = 4,000 Population of the city in 2000 = 40,000 + 4,000 = 44,000
Most Upvoted Answer
The population of a city was 40,000 in the year 1999. It increased at ...
The population of a city in the year 1999 was 40,000 and it increased at the rate of 10% per year. We need to find the population at the end of the year 2000.
Initial Population: 40,000
Rate of Increase: 10% per year
To find the population at the end of the year 2000, we need to calculate the population after one year of growth.
First, let's calculate the population increase for one year:
Population Increase = Initial Population * Rate of Increase
= 40,000 * 0.10
= 4,000
Next, we add the population increase to the initial population to find the population at the end of the year 2000:
Population at the end of 2000 = Initial Population + Population Increase
= 40,000 + 4,000
= 44,000
Therefore, the population at the end of the year 2000 is 44,000.
The correct answer is option (b) 44,000.
Initial Population: 40,000
Rate of Increase: 10% per year
To find the population at the end of the year 2000, we need to calculate the population after one year of growth.
First, let's calculate the population increase for one year:
Population Increase = Initial Population * Rate of Increase
= 40,000 * 0.10
= 4,000
Next, we add the population increase to the initial population to find the population at the end of the year 2000:
Population at the end of 2000 = Initial Population + Population Increase
= 40,000 + 4,000
= 44,000
Therefore, the population at the end of the year 2000 is 44,000.
The correct answer is option (b) 44,000.
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Community Answer
The population of a city was 40,000 in the year 1999. It increased at ...
Population of the city in 1999 = 40,000 Percentage increased = 10% Therefore 10% of 40,000 = 10/100 × 40,000 = 4,000 Population of the city in 2000 = 40,000 + 4,000 = 44,000
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The population of a city was 40,000 in the year 1999. It increased at the rate of 10% p.a. Find the population at the end of the year 2000.a)35000b)44000c)40000d)None of theseCorrect answer is option 'B'. Can you explain this answer?
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