The population of a city was 30,000 in the year 2011. It increased at ...
Population of the city in 2011 = 30,000
Percentage increased = 5%
Therefore 5% of 30,000 = 5/100 × 30,000 = 1,500
Population increased in 2 years = 1,500 × 2 = 3,000
Therefore population in 2013 = 30,000 + 3,000 = 33,000
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The population of a city was 30,000 in the year 2011. It increased at ...
**Given:**
- The population of a city in the year 2011 = 30,000
- Rate of increase = 5% p.a.
**To find:**
- Population at the end of the year 2013
**Solution:**
1. Calculate the increase in population per year.
- Rate of increase = 5%
- Increase per year = 5% of the population in the previous year
- Increase per year = (5/100) * 30,000 = 1,500
2. Calculate the population at the end of each year.
- Population in 2011 = 30,000
- Population in 2012 = Population in 2011 + Increase per year
= 30,000 + 1,500 = 31,500
- Population in 2013 = Population in 2012 + Increase per year
= 31,500 + 1,500 = 33,000
3. Therefore, the population at the end of the year 2013 is 33,000.
**Answer:**
The population at the end of the year 2013 is 33,000. Therefore, option A is correct.
The population of a city was 30,000 in the year 2011. It increased at ...
Population of the city in 2011 = 30,000 Percentage increased = 5% Therefore 5% of 30,000 = 5/100 × 30,000 = 1,500 Population increased in 2 years = 1,500 × 2 = 3,000Therefore population in 2013 = 30,000 + 3,000 = 33,000
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